【发布时间】:2014-04-20 14:30:13
【问题描述】:
我有一个这样的表格:
<table id="preview">
<tbody>
<tr>
<td>01/01/2010</td>
<td>Credit</td>
<td>1000</td>
</tr>
<tr>
<td>01/05/2010</td>
<td>Debit</td>
<td>200</td>
</tr>
<tr>
<td>01/09/2010</td>
<td>Debit</td>
<td>400</td>
</tr>
<tr>
<td>01/11/2010</td>
<td>Debit</td>
<td>100</td>
</tr>
</tbody>
</table>
现在我需要创建一个数组来发送(ajax/php),如下所示:
$ajaxArray = array( 0 => array(From => "01/01/2010", //1st td of the 1st Row
To => "01/05/2010", //1st td of the 2nd Row
Type => "Credit",
Amount => 1000.00),
1 => array(From => "01/05/2010", //1st td of the 2nd Row
To => "01/09/2010", //1st td of the 3th Row
Type => "Debit",
Amount => 200.00),
2 => array(From => "01/09/2010", //1st td of the 3th Row
To => "01/11/2010", //1st td of the 4th Row
Type => "Debit",
Amount => 400.00),
3 => array(From => "01/11/2010", //1st td of the 4th Row
To => "01/01/2012", //Value in $last_date var
Type => "Debit",
Amount => 100.00)
);
我尝试使用此代码:
$('#preview > tbody > tr').each(function() {
var from = $('td:eq(0) ', this).text();
var type = $('td:eq(1) ', this).text();
var amount = $('td:eq(2) ', this).text();
ajaxArray.push({
From: from,
Type: type,
Amount: amount
});
});
如您所见,我无法获得“至”日期值。 “To”日期值是下一行的第一个 TD 中包含的日期,最后一行除外,其中该值位于 $last_date 变量中。
提前致谢
【问题讨论】:
标签: javascript jquery arrays foreach