bash脚本中嵌套for循环内无法识别的变量

Question

我正在尝试在 bash 脚本中遍历两个数组，这是变量的声明：s

declare -a servers=("server1" "server2")
declare -a services=("service1" "service2")

这是我的循环：

for j in "${servers[@]}";do
            'ssh -q -o StrictHostKeyChecking=no user@'$j';
            '"for i in "${services[@]}";do echo "$i status in $j"; 
"'/etc/init.d/service-'$i' status'"; done"''
done

我在尝试执行它时遇到下一个错误，看起来变量 i 是空的并且它没有得到任何值：

for i in service1' 'service2;do echo ' status in 'server1; /etc/init.d/service- status; done'
for i in service1: command not found

Answer 1

应该是这样的：

declare -a servers=("server1" "server2")
declare -a services=("service1" "service2")

for server in ${servers[@]}; do
    for service in ${services[@]}; do
        ssh user@$server /etc/init.d/service-$service status
    done
done