3次尝试的Python用户名和密码

Question

刚开始使用 python 并为此绞尽脑汁，但似乎无法正确解决。

print('Enter correct username and password combo to continue')
count=0
password=Hytu76E
username=bank_admin

while password!='Hytu76E' and username!='bank_admin' and count<4:
    username=input('Enter username: ') and password=input('Enter password: ')

    if password=='Hytu76E' and username=='bank_admin':
     print('Access granted')

    else:
        print('Access denied. Try again.')
        count-=1

语法错误，无法分配给第 6 行 username=input 上的运算符。

Answer 1

你可以使用for循环：

#!/usr/bin/python3

for _ in range(3):
    usr = input("Enter username: ")
    psw = input("Enter password: ")
    
    if usr == "bank_admin" and psw == "Hytu76E":
        print("Access Granted!")
        break
    else:
        print("Access Denied!")
    print("Try Again!")
else:
    print("No more attemps!")

Answer 2

在这里试试这个（我尝试尽可能少地更改您的代码，以便您自己识别相同的逻辑）

print('Enter correct username and password combo to continue')
count = 0

# "" or '' because you are assigning a value string into it
password = ""
username = ""

# looping will continue when wrong input for three times and ask again...
while password!='Hytu76E' and username!='bank_admin' and count < 3:
    # you are collecting user input from CLI separately (you can not assign and operator to such operation as per your code ;)
    username = input("Enter username: ")
    password = input("Enter password: ")

    if password=='Hytu76E' and username=='bank_admin':
     # if match, grand and break
     print('Access granted')
     break

    else:
        print('Access denied. Try again.')
        count+=1     # as per gbse, in the comments, you will need the + to count up

代码中的问题：

# you are assigning string value, what for? this would make the loop hit positive the first time
password=Hytu76E       # string assignment error in syntax, anyway
username=bank_admin    # string assignment error in syntax, anyway

# you can not assigning and operator in the input because of no if condition in this line, also you should compare the values of the input
username=input('Enter username: ') and password=input('Enter password: ')

# if code is ok, then move outside the loop in the case when the user enters the first time good answers
if password=='Hytu76E' and username=='bank_admin':
   print('Access granted')

    else:
        print('Access denied. Try again.')

        # you are decremented the counter which would never leave teh loop at 4, you should add one on each iteration so count+=1 (count = count + 1) 
        count-=1

Answer 3

修复了代码以实现您想要做的事情：

print('Enter correct username and password combo to continue')
count=0
while count < 3:
    username = input('Enter username: ')
    password = input('Enter password: ')
    if password=='Hytu76E' and username=='bank_admin':
        print('Access granted')
        break
    else:
        print('Access denied. Try again.')
        count += 1

所做的更改：

• 删除了username和password的定义，因为它是多余的，可以省略
• 将while 语句更改为计算count 的3 次迭代
• 仅在if 语句中而不是在while 中验证凭据
• 将count的递减改为递增（从count -=改为count +=）
• break 输入正确凭据时的循环

Answer 4

首先，您可以删除您在开始时为密码和用户名提供的初始定义，并将 while 循环更改为 while count

所以它看起来像：

print('enter the correct username and password combo to continue')
count = 0
while count<4:

如果我们保持它以前的样子，那将是不必要的，并且会使您的程序更加混乱。

要修复您的语法错误，您需要删除用户名和密码之间的 和，所以中间看起来更像这样：

username = input('Enter username: ')
password = input('Enter password: ')

然后最后你想将 count-=1 更改为 count+=1，因为如果每次都取走一个，它永远不会达到 4，你的循环将是无限的，这不是你想要实现的。

这是整个修复：

print('Enter correct username and password combo to continue')
count=0
while count<4:
    username=input('Enter username: ')
    password=input('Enter password: ')
    if password=='Hytu76E' and username=='bank_admin':
        print('Access granted')
        count=5
    else:
        print('Access denied. Try again.')
        count+=1

这是我所做的更改列表：

• 删除了第 3 行和第 4 行中的密码和用户名定义

• 将您的 while 循环更改为 while

• 删除了 username=input 和 password=input 之间的和中间

• 在 if 语句后添加 count=5 以便循环结束

Answer 5

我认为这就是您要查找的内容：接受用户名和密码并根据代码中提到的特定密码进行验证，最大尝试限制为 3

print('Enter correct username and password combo to continue')
count=1

while count<4:
    username=input('Enter username: ')
    password=input('Enter password: ')
    if password=='Hytu76E' and username=='bank_admin':
        print('Access granted')
        count=5
    else:
        print('Access denied. Try again.')
        count+=1