【发布时间】:2015-04-08 17:32:33
【问题描述】:
我同样从文本文件中读取:
George Washington, 2345678
John Adams, 3456789
Thomas Jefferson, 4567890
James Madison, 0987654
James Monroe, 9876543
John Quincy Adams, 8765432
Andrew Jackson, 7654321
Martin Van Buren, 6543210
William Henry Harrison, 5432109
John Tyler, 4321098
删除名称的功能有效,但是当它成功时, printf 语句将继续在命令窗口中循环。我尝试在循环结束时使用 break 语句,但这只会导致说找不到名称。有人可以提供任何见解吗?
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
//Creates node for holding student's information
struct node
{
char name [50];
int id;
struct node *next;
}*head;
//Create Function Prototypes
void readDataFile ();
void insert(char *inName, char *inID);
void display(struct node *d);
int deleteID(int num);
void deleteName(char *delete_name);
//Main function
int main()
{
//Declare variables
int i, num, delete_id, id;
char *name;
char nameDelete [50];
char nameInsert [50];
struct node *n;
//initialize link list
head = NULL;
//Read in file
readDataFile();
//Create list of operations utilized in program
while (1)
{
printf("\nList Operations\n");
printf("===============\n");
printf("1.Insert\n");
printf("2.Display\n");
printf("3.Delete by ID\n");
printf("4.Delete by Name\n");
printf("5.Exit\n");
printf("Enter your choice : ");
if(scanf("%d", &i) <= 0)
{
printf("Enter only an Integer\n");
exit(0);
}
else
{
switch(i)
{
case 1:
getchar();
printf("Enter the name to insert:");
scanf("%[^\n]s", nameInsert);
printf("\nEnter the ID associated with the name: ");
scanf("%d", &id);
break;
case 2:
if (head == NULL)
printf("List is Empty\n");
else
{
printf("Elements in the list are:\n");
}
display(n);
break;
case 3:
if(head == NULL)
printf("List is Empty\n");
else
{
printf("Enter the ID number to delete: ");
scanf("%d", &delete_id);
}
if(deleteID(delete_id))
printf("%d deleted successfully \n", delete_id);
else
printf("%d not found in the list\n", delete_id);
break;
case 4:
getchar();
if(head == NULL)
printf("List is Empty\n");
else
{
printf("Enter name to delete: ");
scanf("%[^\n]s", nameDelete);
printf("Checking for name %s...\n", nameDelete);
printf("%s not found in the list\n", nameDelete);
deleteName(nameDelete);
}
break;
case 5:
return 0;
default:
printf("Invalid option\n");
}
}
}
return 0;
}
//Define the functions
//Function to delete by name
void deleteName(char *delete_name)
{
//Create temporary and helper node
struct node *temp, *helper;
//Set temp equal to head
temp = head;
//Loop until the end of the list
while(temp != NULL)
{
if(strcmp(temp->name, delete_name) == 0)
{
if(temp == head)
{
head = temp->next;
free(temp);
printf("Found %s!\n", delete_name);
printf("%s deleted successfully\n", delete_name);
}
else
{
helper->next = temp->next;
free(temp);
printf("Found %s!\n", delete_name);
printf("%s deleted successfully\n", delete_name);
}
}
else
{
helper = temp;
temp = temp->next;
}
}
break;
}
【问题讨论】:
-
为什么不在
deleteName()中的while循环内的if (temp == head) { … } else { … }语句后面加上break;(或return;)? -
问题在于 while 循环条件。 temp 可能没有到达链表的末尾。更正以匹配逻辑
-
能否请您说明您尝试将
break放置在何处?没有它,很难看出你为什么出错了。 -
删除识别出的节点后需要break。! :)
-
我实际上发现了哪里出错了。谢谢大家的见解!
标签: c function loops while-loop linked-list