不断循环这个猜谜游戏

Question

我对 java 还很陌生，我想知道如何在用户猜对后重新设置这个游戏以询问另一个数字？

到目前为止，这是我的代码：

import java.util.Scanner;
public class Question2 {

   public static void main(String args[]) {
      Scanner keyboard = new Scanner(System.in);
         int count = 0;
         int a = 1 + (int) (Math.random() * 99);
         int guess = 0;

      System.out.println("Welcome to the Number Guessing Game");
      System.out.print("Guess a number between 0 and 100 or enter -1 to end: ");

    while (guess != a) {
    guess = keyboard.nextInt();
     count++;
    if (guess < 0 || guess > 100){
     if(guess == -1){
        System.out.print("Thank you for playing the game!");
             break;
      }
        System.out.print("Out of bounds. Try Again: ");
        continue;
    }
    if (guess > a) {
        System.out.print("The number is lower. Try again: ");
    }
    else if (guess < a) {
        System.out.print("The number is higher. Try again: ");
    }
    else if (guess == a) {
    System.out.println("Congratulations. You guessed the number in "
    + count + " tries!");
    }  
   }

}
}

Answer 1

只需将整个代码（扫描仪初始化除外）包装在始终正确的while 循环中。这样，当一场比赛结束时，它将开始新的一场比赛。然后，当用户输入-1 时，不要使用break 执行游戏的while 循环，而只需使用System.exit(0)，它会以0 的状态码结束您的程序，表示程序执行成功。

public static void main(String[] args) throws IOException {
    Scanner keyboard = new Scanner(System.in);
    while (true) {
        int count = 0;
        int a = 1 + (int) (Math.random() * 99);
        int guess = 0;

        System.out.println("Welcome to the Number Guessing Game");
        System.out.print("Guess a number between 0 and 100 or enter -1 to end: ");

        while (guess != a) {
            guess = keyboard.nextInt();
            count++;
            if (guess < 0 || guess > 100) {
                if (guess == -1) {
                    System.out.print("Thank you for playing the game!");
                    System.exit(0);
                }
                System.out.print("Out of bounds. Try Again: ");
                continue;
            }
            if (guess > a) {
                System.out.print("The number is lower. Try again: ");
            } else if (guess < a) {
                System.out.print("The number is higher. Try again: ");
            } else if (guess == a) {
                System.out.println("Congratulations. You guessed the number in "
                        + count + " tries!");
            }
        }
    }
}

Answer 2

将您的代码包装在while (true) 中，这将永远持续运行您的代码。确保在每场比赛后更新您的随机a 和您的count。然后从那里检查猜测是否曾经是-1 和return。当您调用return 时，它将结束结束游戏的方法。

Scanner keyboard = new Scanner(System.in);
while (true){
    int count = 0;
    int a = 1 + (int) (Math.random() * 99);
    int guess = 0;
    System.out.println("Welcome to the Number Guessing Game");
    System.out.print("Guess a number between 0 and 100 or enter -1 to end: ");

    while (guess != a) {
        guess = keyboard.nextInt();
        count++;
        if (guess==-1){
            System.out.print("Thank you for playing the game!");
            return;
        }else if (guess < 0 || guess > 100){
            System.out.print("Out of bounds. Try Again: ");
            continue;
        }
        if (guess > a) {
            System.out.print("The number is lower. Try again: ");
        }
        else if (guess < a) {
            System.out.print("The number is higher. Try again: ");
        }
        else if (guess == a) {
            System.out.println("Congratulations. You guessed the number in "
                    + count + " tries!");
        }  
    }

}

Answer 3

你需要：

• 将你的结束游戏条件移动到while 条件中，像这样while(guess != -1)
• 在循环中移动欢迎问候
• 在游戏循环结束后移动谢谢问候
• 当用户赢得游戏时重置 count 和 a 以便重新开始
• 在每次迭代时重置guess

现在即使玩家猜到了数字，循环不会结束，游戏循环只能有意停止（输入 -1 = 当前中断条件） ：

import java.util.Scanner;
public class Question2 {
    public static void main(String args[]) {
        Scanner keyboard = new Scanner(System.in);
        int count = 0;
        int a = 1 + (int) (Math.random() * 99);
        int guess = 0;

        System.out.println("Welcome to the Number Guessing Game");
        while (guess != -1) {
            System.out.print("Guess a number between 0 and 100 or enter -1 to end: ");
            guess = keyboard.nextInt();
            count++;
            if (guess < 0 || guess > 100){
                System.out.print("Out of bounds. Try Again: ");
                continue;
            }
            if (guess > a) {
                System.out.print("The number is lower. Try again: ");
            }
            else if (guess < a) {
                System.out.print("The number is higher. Try again: ");
            }
            else if (guess == a) {
                a = 1 + (int) (Math.random() * 99);
                System.out.println("Congratulations. You guessed the number in " + count + " tries!");
                count = 0;
            }
            guess = 0;
        }
        System.out.print("Thank you for playing the game!");
}

代码可以重构更多，例如将功能提取到函数中以使代码更具可读性。如果变量发生变化或出现更多情况，这也会导致更容易维护。例如代码可以这样重构：

import java.util.Scanner;
public class Question2 {
    public static void main(String args[]) {
        Scanner keyboard = new Scanner(System.in);
        int a = 0;
        int count = 0;
        int guess = 0;

        startNewGame();

        System.out.println("Welcome to the Number Guessing Game");

        while (guess != -1) {
            System.out.print("Guess a number between 0 and 100 or enter -1 to end: ");
            guess = keyboard.nextInt();
            count++;
            if (guess < 0 || guess > 100){
                System.out.print("Out of bounds. Try Again: ");
                continue;
            }
            if (guess > a) {
                System.out.print("The number is lower. Try again: ");
            }
            else if (guess < a) {
                System.out.print("The number is higher. Try again: ");
            }
            else if (guess == a) {
                System.out.println("Congratulations. You guessed the number in " + count + " tries!");
                startNewGame();
            }
            resetGuess();
        }
        System.out.print("Thank you for playing the game!");
    }

    private static int generateNewA() {
        return 1 + (int) (Math.random() * 99);
    }

    private static void startNewGame() {
        a = generateNewA();
        count = 0;
    }

    private static void resetGuess() {
        guess = 0;
    }
}

另一种解决方案是使用两个嵌套循环，但 IMO 对于这种情况 loop in a loop 太多了，使得源代码变得不必要的复杂。