如何迭代 JSON 结构？ [复制]

Question

我有以下 JSON 结构：

[{ "id":"10", "class": "child-of-9" }, { "id": "11", "classd": "child-of-10" }]

如何使用 JavaScript 对其进行迭代？

Answer 1

var arr = [ {"id":"10", "class": "child-of-9"}, {"id":"11", "class": "child-of-10"}];
    
for (var i = 0; i < arr.length; i++){
  document.write("<br><br>array index: " + i);
  var obj = arr[i];
  for (var key in obj){
    var value = obj[key];
    document.write("<br> - " + key + ": " + value);
  }
}

注意：for-in 方法对于简单对象来说很酷。与 DOM 对象一起使用不是很聪明。

Answer 2

取自jQuery docs：

var arr = [ "one", "two", "three", "four", "five" ];
var obj = { one:1, two:2, three:3, four:4, five:5 };

jQuery.each(arr, function() {
  $("#" + this).text("My id is " + this + ".");
  return (this != "four"); // will stop running to skip "five"
});

jQuery.each(obj, function(i, val) {
  $("#" + i).append(document.createTextNode(" - " + val));
});

Answer 3

使用for...of：

var mycars = [{name:'Susita'}, {name:'BMW'}];

for (var car of mycars) 
{
  document.write(car.name + "<br />");
}

结果：

Susita
BMW

Answer 4

如果不容易，请告诉我：

var jsonObject = {
  name: 'Amit Kumar',
  Age: '27'
};

for (var prop in jsonObject) {
  alert("Key:" + prop);
  alert("Value:" + jsonObject[prop]);
}

Answer 5

如果这是你的dataArray:

var dataArray = [{"id":28,"class":"Sweden"}, {"id":56,"class":"USA"}, {"id":89,"class":"England"}];

然后：

$(jQuery.parseJSON(JSON.stringify(dataArray))).each(function() {  
         var ID = this.id;
         var CLASS = this.class;
});

Answer 6

从http://www.w3schools.com复制粘贴，不需要JQuery开销。

var person = {fname:"John", lname:"Doe", age:25};

var text = "";
var x;
for (x in person) {
    text += person[x];
}

结果：John Doe 25

Answer 7

mootools 示例：

var ret = JSON.decode(jsonstr);

ret.each(function(item){
    alert(item.id+'_'+item.classd);
});

Answer 8

你可以使用像 objx 这样的迷你库 - http://objx.googlecode.com/

你可以这样写代码：

var data =  [ {"id":"10", "class": "child-of-9"},
              {"id":"11", "class": "child-of-10"}];

// alert all IDs
objx(data).each(function(item) { alert(item.id) });

// get all IDs into a new array
var ids = objx(data).collect("id").obj();

// group by class
var grouped = objx(data).group(function(item){ return item.class; }).obj()

还有更多“插件”可让您处理此类数据，请参阅http://code.google.com/p/objx-plugins/wiki/PluginLibrary

Answer 9

使用嵌套对象，可以通过递归函数检索：

function inside(events)
  {
    for (i in events) {
      if (typeof events[i] === 'object')
        inside(events[i]);
      else
      alert(events[i]);
    }
  }
  inside(events);

其中 events 是 json 对象。

Answer 10

Marquis Wang's 可能是使用 jQuery 时的最佳答案。

在纯 JavaScript 中，使用 JavaScript 的 forEach 方法有一些非常相似的东西。 forEach 将函数作为参数。然后将为数组中的每个项目调用该函数，并将所述项目作为参数。

简短易懂：

var results = [ {"id":"10", "class": "child-of-9"}, {"id":"11", "classd": "child-of-10"} ];

results.forEach(function(item) {
    console.log(item);
});

Answer 11

这是一个纯注释的 JavaScript 示例。

  <script language="JavaScript" type="text/javascript">
  function iterate_json(){
            // Create our XMLHttpRequest object
            var hr = new XMLHttpRequest();
            // Create some variables we need to send to our PHP file
            hr.open("GET", "json-note.php", true);//this is your php file containing json

            hr.setRequestHeader("Content-type", "application/json", true);
            // Access the onreadystatechange event for the XMLHttpRequest object
            hr.onreadystatechange = function() {
                if(hr.readyState == 4 && hr.status == 200) {
                    var data = JSON.parse(hr.responseText);
                    var results = document.getElementById("myDiv");//myDiv is the div id
                    for (var obj in data){
                    results.innerHTML += data[obj].id+ "is"+data[obj].class + "<br/>";
                    }
                }
            }

            hr.send(null); 
        }
</script>
<script language="JavaScript" type="text/javascript">iterate_json();</script>// call function here

Answer 12

var jsonString = `{
    "schema": {
        "title": "User Feedback",
        "description": "so",
        "type": "object",
        "properties": {
            "name": {
                "type": "string"
            }
        }
    },
    "options": {
        "form": {
            "attributes": {},
            "buttons": {
                "submit": {
                    "title": "It",
                    "click": "function(){alert('hello');}"
                }
            }
        }
    }
}`;

var jsonData = JSON.parse(jsonString);

function Iterate(data)
{
    jQuery.each(data, function (index, value) {
        if (typeof value == 'object') {
            alert("Object " + index);
            Iterate(value);
        }
        else {
            alert(index + "   :   " + value);
        }
    });
}

Iterate(jsonData);

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

Answer 13

浏览 JSON 文档的另一种解决方案是 JSONiq（在 Zorba 引擎中实现），您可以在其中编写如下内容：

jsoniq version "1.0";

let $doc := [
  {"id":"10", "class": "child-of-9"},
  {"id":"11", "class": "child-of-10"}
]
for $entry in members($doc)             (: binds $entry to each object in turn :)
return $entry.class                     (: gets the value associated with "class" :)

你可以在http://try.zorba.io/上运行它