If 语句简单答案

【问题标题】：If Statement SimpleIf 语句简单
【发布时间】：2020-02-22 03:46:45
【问题描述】：

有没有办法让这个 ELIF 语句更简单，顺便说一下这段代码不起作用。改变的变量是 APPOINTMENT

elif (rut == '80010900-0' and agental_launch != "" and 'TAL'  in appointment) or
        (rut == '80010900-0' and agental_launch != "" and 'IQQ'  in appointment) or
        (rut == '80010900-0' and agental_launch != "" and 'ANF'  in appointment) or
        (rut == '80010900-0' and agental_launch != "" and 'MJS'  in appointment) or
        (rut == '80010900-0' and agental_launch != "" and 'QTV'  in appointment) or
        (rut == '80010900-0' and agental_launch != "" and 'SVE'  in appointment) or
        (rut == '80010900-0' and agental_launch != "" and 'PMC'  in appointment) or
        (rut == '80010900-0' and agental_launch != "" and 'CHB'  in appointment):
        df.at[idx,'REBATE'] = round(int(monto_neto)*0.35)

【问题讨论】：

(p and q) or (p and r) <=> p and (q or r)

标签： python if-statement variables var

【解决方案1】：

你可以这样做：

elif rut == '80010900-0' and agental_launch != "" and any(elem in appointment for elem in ['TAL','IQQ','ANF','MJS','QTV','SVE','PMC','CHB']):
     df.at[idx,'REBATE'] = round(int(monto_neto)*0.35)

【讨论】：

嘿 Vasilis，ANY 的反面是什么？

【解决方案2】：

将any 用于成为单行的最后一个条件：

elif rut == '80010900-0' and agental_launch != "" and any(x in appointment for x in ['TAL','IQQ','rest of strings to match...']):

【讨论】：

ANY() 的反义词是什么？
但这给我带来了一切！，在示例中任何（x 在 ['TAL' 中的 x 约会，.. 我需要相反的，比如 NOT ANY？是可能的吗？
just not any then: 仅当约会中不包含子字符串时才为真