这是另一个有趣的想法。我想出了以下Enumeration 基类:
public abstract class Enumeration<T>
where T : Enumeration<T>
{
protected static int nextOrdinal = 0;
protected static readonly Dictionary<int, Enumeration<T>> byOrdinal = new Dictionary<int, Enumeration<T>>();
protected static readonly Dictionary<string, Enumeration<T>> byName = new Dictionary<string, Enumeration<T>>();
protected readonly string name;
protected readonly int ordinal;
protected Enumeration(string name)
: this (name, nextOrdinal)
{
}
protected Enumeration(string name, int ordinal)
{
this.name = name;
this.ordinal = ordinal;
nextOrdinal = ordinal + 1;
byOrdinal.Add(ordinal, this);
byName.Add(name, this);
}
public override string ToString()
{
return name;
}
public string Name
{
get { return name; }
}
public static explicit operator int(Enumeration<T> obj)
{
return obj.ordinal;
}
public int Ordinal
{
get { return ordinal; }
}
}
它基本上有一个类型参数,因此序数可以在不同的派生枚举中正常工作。上面 Jon 的 Operator 示例变为:
public class Operator : Enumeration<Operator>
{
public static readonly Operator Plus = new Operator("Plus", (x, y) => x + y);
public static readonly Operator Minus = new Operator("Minus", (x, y) => x - y);
public static readonly Operator Times = new Operator("Times", (x, y) => x * y);
public static readonly Operator Divide = new Operator("Divide", (x, y) => x / y);
private readonly Func<int, int, int> op;
// Prevent other top-level types from instantiating
private Operator(string name, Func<int, int, int> op)
:base (name)
{
this.op = op;
}
public int Execute(int left, int right)
{
return op(left, right);
}
}
这有一些好处。
- 顺序支持
- 转换为
string 和 int 使 switch 语句可行
- GetType() 将为派生的 Enumeration 类型的每个值提供相同的结果。
-
System.Enum 中的静态方法可以添加到 Enumeration 基类中以实现相同的功能。