按名称过滤键包含字符串答案

【问题标题】：filter keys by names contains string按名称过滤键包含字符串
【发布时间】：2018-11-20 18:03:23
【问题描述】：

我想按名称过滤 myArray 键包含字符串“item”（所有“item1”、“item2”、“item3”等）

const combined = myArray.map(e => Object.assign(e, MyArrayDefinition.find(k => k.item === e.item)));

我已经用 .includes 尝试过这个，但它不起作用

const combined = myArray.map(e => Object.assign(e, MyArrayDefinition.find(k => k.includes('item') === e.item)));

我的数组

const myArray = [{
            "shop": "shop1",
            "item1": "my apple 1",
            "item2": "my carrot 1",

        },  {
            "shop": "shop2",
            "item1": "my apple 0",
            "item2": "my carrot 1",

        }, {
            "shop": "shop2",
            "item1": "my apple 1",
            "item2": "my carrot 0",

        }, ];

        const MyArrayDefinition = [ {
            "item": "my apple 0",
            "color": "red",
            "group": "my fruit",
            "score": 0
        }, {
            "item": "my carrot 1",
            "color": "orange",
            "group": "my vegetable",
            "score": 1
        }, {
            "item": "my apple 1",
            "color": "red",
            "group": "my fruit",
            "score": 1
        }, {
            "item": "my carrot 0",
            "color": "orange",
            "group": "my vegetable",
            "score": 0
        }];

【问题讨论】：

请添加想要的结果...
您是在比较item1 与item 还是item2 与item？
item2 会发生什么？
我将 item1 和 item2 与 item 进行比较以获取它们的颜色和组
请将结果添加到问题中并添加为什么项目是一项而不是另一项。

标签： javascript arrays object filter include

【解决方案1】：

类似：

const filtered = myArray.map((obj) => {
    const objKeys = Object.keys(obj);
    const result = objKeys.reduce((acc, k) => {
        if (k.match(/item/)) { // just keys withe "item"
            acc[k] = obj[k];
        }

        return acc;
    }, {});

    return result;
})

【讨论】：

【解决方案2】：

如果需要一个包含所有找到的项目的数组，那么您可以过滤键并获取定义数组的项目。

var array = [{ shop: "shop1", item1: "my apple 1", item2: "my carrot 1" }, { shop: "shop2", item1: "my apple 0", item2: "my carrot 1" }, { shop: "shop2", item1: "my apple 0", item2: "my carrot 0" }],
    definition = [{ item: "my apple 0", color: "red", group: "my fruit", score: 0 }, { item: "my carrot 1", color: "orange", group: "my vegetable", score: 1 }, { item: "my apple 1", color: "red", group: "my fruit", score: 1 }, { item: "my carrot 0", color: "orange", group: "my vegetable", score: 0 }],
    result = array.map(o => ({
        shop: o.shop,
        items: Object
            .keys(o)
            .filter(k => k.startsWith('item'))
            .map(k => definition.find(({ item }) => item === o[k]))
    }));

console.log(result);

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【讨论】：

非常感谢您的帮助！但它是一个多维对象。我需要带有对象的简单数组。像这样 [{ shop:"shop1", "item": "my apple 1", "color": "red", "group": "my fruit", "score": 1},{ shop:"shop1 ", "item": "my apple 1", "color": "red", "group": "my fruit", "score": 1},etc]
你要带什么东西？ item1 或 item2?
我要带走所有物品
第一个对象的数组应该如何查找？
每一个物件都是一个独特的物品+独特的商店，分数是它们的总和

【解决方案3】：

另一种方法是使用函数 filter 和函数 includes 来过滤带有键 === item 的对象，并与数组 MyArrayDefinition 一起存在。

此示例具有以下对象，其值在 MyArrayDefinition 中不存在：

{  
    "shop": "shop33",
    "item1": "my apple 33",  
    "item2": "my carrot 33"
}

const myArray = [{  "shop": "shop1",  "item1": "my apple 1 my fruit",  "item2": "my carrot 1",}, {  "shop": "shop2",  "item1": "my apple 0",  "item2": "my carrot 1",}, {  "shop": "shop2",  "item1": "my apple 0",  "item2": "my carrot 0",}, {  "shop": "shop33",  "item1": "my apple 33",  "item2": "my carrot 33",}],
      MyArrayDefinition = [{  "item": "my apple 0",  "color": "red",  "group": "my fruit",  "score": 0}, {  "item": "my carrot 1",  "color": "orange",  "group": "my vegetable",  "score": 1}, {  "item": "my apple 1",  "color": "red",  "group": "my fruit",  "score": 1}, {  "item": "my carrot 0",  "color": "orange",  "group": "my vegetable",  "score": 0}],
      mappedItems = MyArrayDefinition.map(({item}) => item), // convert to an array with only values from item.
      result = myArray.filter(o => Object.keys(o).some(k => k.includes('item') && mappedItems.includes(o[k]))); // get the object with at least one key === item and which value exists within mappedItems.

console.log(result);

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【讨论】：