在python中加载文件夹的最大csv文件

Question

我的电脑上有一个文件夹，其中保存了几个文件。如何仅自动加载最大的文件（以 kb 为单位）？

现在我可以使用：

#Sort it with the help of windows, biggest file on top and then:
import pandas as pd
df = pd.read_csv(r'C:\...\FileABC.csv') #when I know FileABC is listed on the top

有没有办法在 python 中自动执行此操作？然后我可以跳过 windows 中的手动调整。

Answer 1

试试这个：

import os
import pandas as pd
basedir = 'C:/Users/viupadhy/Desktop/Stackoverflow'
names = os.listdir(basedir)
paths = [os.path.join(basedir, name) for name in names]
sizes = [(path, os.stat(path).st_size) for path in paths]
file = max(sizes, key=lambda x: x[1])
print(file)

df = pd.read_csv(file[0])
df

输出：

Answer 2

一个简单的方法：

import os


def find_largest_file(path):
    largest = None
    max_size = 0
    for filename in os.listdir(path):
        if os.path.isfile(filename):
            size = os.path.getsize(filename)
            if size > max_size:
                largest = filename
                max_size = size
    return largest


print(find_largest_file(path))
# ... whaterver largest file you have in `path`.

这可以通过仅过滤.csv 扩展等来进一步改进。

Answer 3

你可以使用类似的东西：

import os
import pandas as pd


folder_path = "C:\\programs\\"

file_list = os.listdir(folder_path)
biggest_file = os.path.join(folder_path, file_list[0])

for file in file_list:
    file_location = os.path.join(folder_path, file)
    size = os.path.getsize(file_location)

    if size > os.path.getsize(biggest_file):
        biggest_file = file_location

df = pd.read_csv(biggest_file)