如何将用户输入的字符串与列表中单词的字符（单个字母）进行比较？

Question

我正在尝试使用 python 创建一个刽子手游戏。我知道还有很多事情要完成，但我正在尝试找出游戏的主要组成部分，即如何将用户输入的字符串（一个字母）与三个随机选择的单词之一中的字母进行比较。

import random

print("Welcome to hangman,guess the five letter word")
words =["china", "ducks", "glass"]
correct_word = (random.choice(words))
guess = input(str("Enter your guess:"))
guess_left = 10
guess_subtract = 1
if guess == "":
    guess_left = guess_left - guess_subtract
    print("you have" + guess_left + "guesses left")

Answer 1

您可以将字符串视为数组/列表。 所以如果你使用循环：

x = ""#let's assume this is the users input
for i in range(len(y)): #y is the string your checking against
    if x == y[i]:

从这里我的想法是，如果它们相等，它将将该字母添加到字符串中

假设字符串是“今天很有趣”，那么会有一个像这样的数组，[""."" 等等，但你必须找到一种方法来考虑空格和撇号。所以如果字母是 == 到字符串的那一部分

#this is a continuation of the code, so under if
thearray[theposition] == the letter

但是看你的代码，你的游戏与普通的不同，所以，也考虑使用一段时间看看

gamewon = False
number of trials = 10

while gamewon == False and number of trials > 0:
    #the whole checking process 
    if x == guess:
       gamewon == True
       print ........# this is if your doing word for word else use 
       the code above
     else:
         number  of trials = number of trials - 1

我想就是这样我知道它有点到处但是你可以随时寻求帮助，我会解释另外我指的是你的代码我认为你可以修复的东西

Answer 2

首先，您应该使用guess = guess.lower() 同时接受a 和A。您必须在字符串中搜索猜测的字符并找到位置。

guess = guess.lower()

# Find the position(s) of the character guessed
pos = [idx for idx,ch in enumerate(correct_word) if ch == guess]

if pos:
    print('Letter Found')

guess_left -= 1

理解for循环的另一种方式是：

pos = []
for idx,ch in enumerate(correct_word):
    if ch == guess:
        pos.append(idx)

Answer 3

我认为你需要一个骨架，然后花一些时间来改进游戏。

import random

print "Welcome to hangman, guess the five letter word"

words = ["china", "ducks", "glass"]
correct_word = (random.choice(words))

trials = 10

for trial in range(trials):
    guess = str(raw_input("Enter character: "))

    if (len(guess) > 1):
        print "You are not allowed to enter more than one character at time"
        continue

    if guess in correct_word:
        print "Well done! '" + guess + "' is in the list!"
    else:
        print "Sorry " + guess + " does not included..."

您的下一步可能是打印出 c_i__ 之类的内容以及剩余的试验次数。玩得开心:)

完成实现后，请花一些时间并使用函数重新实现它。