【发布时间】:2012-11-29 04:25:15
【问题描述】:
有没有更清洁的方法来做到这一点?它不编译
$object1->name = 'my_name';
$object1->address = 'address';
$object2->somefield->($object1->name) = $object1;
只有当我分配给另一个变量 $object1->name
时它才有效$object1->name = 'my_name';
$object1->address = 'address';
$temp = $object1->name;
$object2->somefield->$temp = $object1;
【问题讨论】:
标签: php