Postgres存储函数如何返回表答案

【问题标题】：How can a Postgres Stored Function return a tablePostgres存储函数如何返回表
【发布时间】：2012-05-06 22:32:48
【问题描述】：

我想了解 Postgres 存储函数如何返回带有已识别列的表。我使用了 return setof returnType:

-- create employeeSearchResult returnType
create type employeeAllReturnType as
(
  id bigserial,
  "positionId" integer,
  "subjectId" bigint,
  "dateEngaged" date,
  "nextKin" text,
  "nrcNo" text,
  dob date,
  father text,
  mother text,
  wife text,
  "userId" integer,
  "statusId" integer,
  "mainCode" text,
  "subCode" text
);


-- Search for emmployee by name
CREATE OR REPLACE FUNCTION "employee_search_by_name"(employeeNameIN text)
returns setof employeeAllReturnType as 
$$
declare
    results record;
    resultsRow employee%rowtype;
    nameIn text;
begin
    nameIn = employeeNameIN || '%';
    for results in select 
        employee.id,-- bigserial NOT NULL,
  employee."positionId",-- integer,
  employee."subjectId",-- bigint NOT NULL,
  employee."dateEngaged",-- date,
  employee."nextKin",-- text,
  employee."nrcNo",-- text,
  employee.dob,-- date,
  employee.father,-- text,
  employee.mother,-- text,
  employee.wife,-- text,
  employee."userId",-- integer NOT NULL,
  employee."statusId",-- integer,
  employee."mainCode",-- character(5) NOT NULL,
  employee."subCode"-- character(10),
     from employee, subject where employee."subjectId" = subject.id and (subject.name1 ILIKE nameIn OR subject.name2 ILIKE nameIn OR subject.name3 ILIKE nameIn OR subject.name4 ILIKE nameIn) loop
      return next results;
    end loop;
end;
$$ language 'plpgsql';

并且还返回 table():

-- Search for emmployee by name
CREATE OR REPLACE FUNCTION "employee_search_by_name"(employeeNameIN text)
returns table (id bigserial,
  position integer,
  subject bigint,
  date_engaged date,
  next_kin text,
  nrc_no text,
  dob date,
  father text,
  mother text,
  wife text,
  user_id integer,
  status_id integer,
  main_code text,
  sub_code text) as 
$$
declare
    results record;
    resultsRow employee%rowtype;
    nameIn text;
begin
    nameIn = employeeNameIN || '%';
    for results in select 
        employee.id,-- bigserial NOT NULL,
        employee."positionId",-- integer,
        employee."subjectId",-- bigint NOT NULL,
        employee."dateEngaged",-- date,
        employee."nextKin",-- text,
        employee."nrcNo",-- text,
        employee.dob,-- date,
        employee.father,-- text,
        employee.mother,-- text,
        employee.wife,-- text,
        employee."userId",-- integer NOT NULL,
        employee."statusId",-- integer,
        employee."mainCode",-- character(5) NOT NULL,
        employee."subCode"-- character(10),
     from employee, subject where employee."subjectId" = subject.id and (subject.name1 ILIKE nameIn OR subject.name2 ILIKE nameIn OR subject.name3 ILIKE nameIn OR subject.name4 ILIKE nameIn) loop
      return next results;
    end loop;
end;
$$ language 'plpgsql';

但两者都有以下格式的输出：

"(1,1,1,2011-12-01,Timea,fg1254,1981-12-27,moses,sarada,timea,1,1,"ADM  ","1         ")"
"(37,3,10,2011-11-11,s,s,2011-11-11,s,s,s,1,1,"OP   ","1         ")"

无论如何我可以有输出，例如从表中选择结果的输出？

"1";1;1;"2011-12-01";"Timea";"fg1254";"1981-12-27";"moses";"sarada";"timea";1;1;"ADM  ";"1         "

这样从前端处理结果数据就不需要解析器了。

【问题讨论】：

标签： postgresql function return

【解决方案1】：

你应该像这样查询你的函数：

SELECT * FROM employee_search_by_name('Bob');

另外，为了简化您的功能，您可以查看RETURN QUERY EXECUTE ... 构造。并且不需要引用plpgsql关键字。

【讨论】：

这里不需要双引号。
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