将段落分解为字符串标记

Question

我能够根据给定的第 n 个字符限制将文本段落分解为子字符串。我的冲突是我的算法正是这样做的，并且正在分解单词。这就是我卡住的地方。如果字符限制出现在一个单词的中间，我怎样才能回溯到一个空格，以便我的所有子字符串都有完整的单词？

这是我正在使用的算法

int arrayLength = 0;
arrayLength = (int) Math.ceil(((mText.length() / (double) charLimit)));

String[] result = new String[arrayLength];
int j = 0;
int lastIndex = result.length - 1;
for (int i = 0; i < lastIndex; i++) {
    result[i] = mText.substring(j, j + charLimit);
    j += charLimit;
}

result[lastIndex] = mText.substring(j);

我正在使用任何第 n 个整数值设置 charLimit 变量。 mText 是带有一段文本的字符串。关于如何改进这一点的任何建议？提前谢谢你。

我收到了很好的回应，所以你知道我做了什么来弄清楚我是否登陆了一个空间，我使用了这个 while 循环。我只是不知道如何从这一点纠正。

while (!strTemp.substring(strTemp.length() - 1).equalsIgnoreCase(" ")) {
    // somehow refine string before added to array
}

Answer 1

不确定我是否正确理解了您想要的内容，但可以回答我的解释：

您可以使用lastIndexOf 找到字符限制之前的最后一个空格，然后检查您是否足够接近您的限制（对于没有空格的文本），即：

int arrayLength = 0;
arrayLength = (int) Math.ceil(((mText.length() / (double) charLimit)));

String[] result = new String[arrayLength];
int j = 0;
int tolerance = 10;
int splitpoint;
int lastIndex = result.length - 1;
for (int i = 0; i < lastIndex; i++) {
    splitpoint = mText.lastIndexOf(' ' ,j+charLimit);
    splitpoint = splitpoint > j+charLimit-tolerance ? splitpoint:j+charLimit;
    result[i] = mText.substring(j, splitpoint).trim();
    j = splitpoint;
}

result[lastIndex] = mText.substring(j).trim();

这将搜索charLimit（示例值）之前的最后一个空格，如果它小于tolerance，则将字符串拆分到那里，如果不是，则在charLimit 拆分。

此解决方案的唯一问题是最后一个 Stringtoken 可能比 charLimit 长，因此您可能需要调整 arrayLength 并循环 while (mText - j > charLimit)

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编辑

运行示例代码：

 public static void main(String[] args) {
    String mText =  "I am able to break up paragraphs of text into substrings based upon nth given character limit. The conflict I have is that my algorithm is doing exactly this, and is breaking up words. This is where I am stuck. If the character limit occurs in the middle of a word, how can I back track to a space so that all my substrings have entire words?";

    int charLimit = 40;
    int arrayLength = 0;
    arrayLength = (int) Math.ceil(((mText.length() / (double) charLimit)));

    String[] result = new String[arrayLength];
    int j = 0;
    int tolerance = 10;
    int splitpoint;
    int lastIndex = result.length - 1;
    for (int i = 0; i < lastIndex; i++) {
        splitpoint = mText.lastIndexOf(' ' ,j+charLimit);
        splitpoint = splitpoint > j+charLimit-tolerance ? splitpoint:j+charLimit;
        result[i] = mText.substring(j, splitpoint);
        j = splitpoint;
    }

    result[lastIndex] = mText.substring(j);

    for (int i = 0; i<arrayLength; i++) {
        System.out.println(result[i]);
    }
}

输出：

I am able to break up paragraphs of text
 into substrings based upon nth given
 character limit. The conflict I have is
 that my algorithm is doing exactly
 this, and is breaking up words. This is
 where I am stuck. If the character
 limit occurs in the middle of a word,
 how can I back track to a space so that
 all my substrings have entire words?

附加编辑： 根据 curiosu 的建议添加了 trim()。它会删除字符串标记周围的空格。