在 SQL Server 中拆分前缀、名字、中间名和姓氏中的全名

Question

我正在尝试使用 SQL Server 将全名拆分为 Prefix、First Name、Middle Name 和 Last Name。

我尝试了以下方法，但由于所需的输出不正确，因此无法正常工作。

代码

SELECT TOP 10 
    ID,
    FullName,
    SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, LEN(FullName)) AS Full_Name,
    SUBSTRING(FullName, 1, CHARINDEX(' ', FullName)) AS Prefix,
    SUBSTRING(FullName, CHARINDEX(' ', FullName), LEN(FullName) - CHARINDEX(' ', REVERSE(FullName)) - CHARINDEX(' ', FullName) + 1) FirstName,
    RIGHT(FullName, CHARINDEX(' ', REVERSE(FullName)) - 1) AS Last_Name,
    LEN(SUBSTRING(FullName, CHARINDEX(' ', FullName), LEN(FullName) - CHARINDEX(' ', REVERSE([FullName)) - CHARINDEX(' ', FullName) + 1)) AS FirstNameChar
FROM
    Names WITH (NOLOCK)
WHERE
    (FullName LIKE 'Mr %' OR 
     FullName LIKE 'Mrs %' OR  
     FullName LIKE 'Miss %' OR  
     FullName LIKE 'Ms %' OR
     FullName LIKE 'Dr %')

当前输出：

ID	FullName	Prefix	FirstName	Last_Name	FirstNameChar
123456	Mr s t Fenech	Mr	s t	Fenech	4

需要的输出：

ID	FullName	Prefix	FirstName	Middle_Name	Last_Name	FirstNameChar
123456	Mr s t Fenech	Mr	s	t	Fenech	1

我想删除名字和姓氏之前的空格，可以看到 FirstNameChar 是 4 而实际上应该是 1 并且还能够拆分中间名。

有人可以帮忙吗？

参考stackoverflow上的问题： SQL- Get the substring after first space and second space in separate columns

SQL: parse the first, middle and last name from a fullname field

Parse Prefix First Middle Last Suffix from full name

Answer 1

如果您确实知道名称的格式始终相同（例如， [prefix][space][first][space][middle][space][last] ），您可以执行以下操作：

SELECT SUBSTRING('Mr s t Fenech', CHARINDEX(' ', 'Mr s t Fenech') + 1, LEN('Mr s t Fenech')) AS Full_Name
, REVERSE(PARSENAME(REPLACE(REVERSE('Mr s t Fenech'), ' ', '.'), 1)) AS Prefix
, REVERSE(PARSENAME(REPLACE(REVERSE('Mr s t Fenech'), ' ', '.'), 2)) AS FirstName
, REVERSE(PARSENAME(REPLACE(REVERSE('Mr s t Fenech'), ' ', '.'), 3)) AS MiddleName
, REVERSE(PARSENAME(REPLACE(REVERSE('Mr s t Fenech'), ' ', '.'), 4)) AS LastName
, LEN(REVERSE(PARSENAME(REPLACE(REVERSE('Mr s t Fenech'), ' ', '.'), 1))) AS PrefixLen
, LEN(REVERSE(PARSENAME(REPLACE(REVERSE('Mr s t Fenech'), ' ', '.'), 2))) AS FirstNameLen
, LEN(REVERSE(PARSENAME(REPLACE(REVERSE('Mr s t Fenech'), ' ', '.'), 3))) AS MiddleNameLen
, LEN(REVERSE(PARSENAME(REPLACE(REVERSE('Mr s t Fenech'), ' ', '.'), 4))) AS LastNameLen

但是将'Mr s t Fenech' 替换为FullName。

Answer 2

此查询适用于所有组合。由于带有空格的前缀是强制性的，因此可以检查带有前缀的 (first_name) 或 (first_name & last_name) 或 (first_name & middle_name & last_name)。

    SELECT TOP 10
     ID
     , FullName
     , SUBSTRING(FullName, 1, CHARINDEX(' ', FullName) - 1) Prefix
     , CASE WHEN CHARINDEX(' ', FullName) = 0 
               THEN NULL
            ELSE SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, (CASE WHEN CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, LEN(FullName))) = 0 
                                                                      THEN LEN(FullName)
                                                                   ELSE CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, LEN(FullName))) - 1
                                                              END)) 
       END FirstName
     , CASE WHEN CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, LEN(FullName))) + 1 + CHARINDEX(' ', FullName), LEN(FullName))) = 0
               THEN NULL
            ELSE SUBSTRING(FullName, CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, LEN(FullName))) + 1 + CHARINDEX(' ', FullName), 
               CASE WHEN CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, LEN(FullName))) = 0
                       THEN LEN(FullName)
                    ELSE ((CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, LEN(FullName))) + 1 + CHARINDEX(' ', FullName), LEN(FullName)))) - 1) END)
       END MiddleName
     , CASE WHEN (CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, LEN(FullName))) + 1 + CHARINDEX(' ', FullName), LEN(FullName))) > 0
               OR CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, LEN(FullName))) > 0)
               THEN CASE WHEN CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, LEN(FullName))) + 1 + CHARINDEX(' ', FullName), LEN(FullName))) + 1 + CHARINDEX(' ', FullName) + CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, LEN(FullName))), LEN(FullName))) = 0
                            THEN RIGHT(FullName, CHARINDEX(' ', REVERSE(FullName)) - 1)
                         ELSE SUBSTRING(FullName, CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, LEN(FullName))) + 1 + CHARINDEX(' ', FullName), LEN(FullName))) + 1 + CHARINDEX(' ', FullName) + CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, LEN(FullName))), LEN(FullName))
                    END
            ELSE NULL
       END LastName
     , LEN(CASE WHEN CHARINDEX(' ', FullName) = 0 
                     THEN NULL
                  ELSE SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, (CASE WHEN CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, LEN(FullName))) = 0 
                                                                          THEN LEN(FullName)
                                                                       ELSE CHARINDEX(' ', SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, LEN(FullName))) - 1
                                                                  END)) 
             END) FirstNameChar
FROM dbo.fullNameTest
WHERE
    (FullName LIKE 'Mr %' OR 
     FullName LIKE 'Mrs %' OR  
     FullName LIKE 'Miss %' OR  
     FullName LIKE 'Ms %' OR
     FullName LIKE 'Dr %');

同时检查这个网址https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=b4a02827d400ac4cadad852bbae96c57