【发布时间】:2022-01-22 11:32:10
【问题描述】:
我按以下方式进行了测试,但它困扰着我如何需要导入具有函数的对象,而不仅仅是导入函数。
这行得通
//service.test.js
const get = require('../../modules/bankUser/model/getRegisteredUser');
get.getRegisteredUser = jest.fn()
.mockImplementationOnce(async () => mock)
.mockImplementationOnce(async () => mockUpdated);
//service.js
const get = require('../model/getRegisteredUser');
const testedFunction () => {
const depositReciver = await get.getRegisteredUser(depositName, depositCpf);
}
这个剂量
//service.test.js
const get = require('../../modules/bankUser/model/getRegisteredUser');
get.getRegisteredUser = jest.fn()
.mockImplementationOnce(async () => mock)
.mockImplementationOnce(async () => mockUpdated);
//service.js
const { getRegisteredUser } = require('../model/getRegisteredUser');
const testedFunction () => {
const depositReciver = await getRegisteredUser(depositName, depositCpf);
}
我正在尝试这个 (way):
//service.test.js
const get = require('../../modules/bankUser/model/getRegisteredUser');
jest.mock('../../modules/bankUser/model/getRegisteredUser');
get.mockImplementationOnce(() => ({ getRegisteredUser: () => mockObject }));
jest 返回这个:
TypeError: get.mockImplementationOnce is not a function
我也试过这样导入
//service.test.js
const { getRegisteredUser } = require('../../modules/bankUser/model/getRegisteredUser');
jest.mock('../../modules/bankUser/model/getRegisteredUser');
getRegisteredUser.mockImplementationOnce(() => ({ getRegisteredUser: () => mockObject }));
编辑
//getRegisteredUser.js
const { getConnection } = require('../../../global/connection');
const getRegisteredUser = async (userName, cpf) => {
const db = await getConnection('Data-Base');
const res = await db.collection('Collection')
.findOne({ userName, cpf });
return res;
};
module.exports = { getRegisteredUser };
【问题讨论】:
-
我认为您需要在导入模块之前调用
jest.mock。是的,解构会提早绑定东西,这会使模拟变得复杂。
标签: javascript unit-testing jestjs