【发布时间】:2022-01-25 12:18:57
【问题描述】:
我想为 loadingTime 函数编写一个单元测试。该函数将timeTable(类型map)转换为一个由0和1组成的结果数组。索引3-5(03:00-05:00),12-14(12:00-14:00)为1,其余为1为0。然后将结果数组分配给rowTable。如何为此编写单元测试?
timeTable: Map<number, Array<from: string to: string>>
0:[{from: "03:00", to: 05:00"}, {from: "12:00", to:"14:00"}]
1:[{from: "00:00", to: "23:00"}]
2:[{from: "00:00", to: "23:00"}]
3:[{from: "00:00", to: "23:00"}]
4:[{from: "00:00", to: "23:00"}]
5:[{from: "00:00", to: "23:00"}]
6:[{from: "00:00", to: "23:00"}]
行表:
rowTable: Row[] = [
{ name: this.allDays.monday, items: new Array(24).fill(1), active: true },
{ name: this.allDays.tuesday, items: new Array(24).fill(1), active: true },
{ name: this.allDays.wednesday, items: new Array(24).fill(1), active: true },
{ name: this.allDays.thursday, items: new Array(24).fill(1), active: true },
{ name: this.allDays.friday, items: new Array(24).fill(1), active: true },
{ name: this.allDays.saturday, items: new Array(24).fill(1), active: true },
{ name: this.allDays.sunday, items: new Array(24).fill(1), active: true }
];
加载时间
loadingTime(): void {
if (this.timeTable) {
let result = [...this.timeTable].reduce((r, [key, value], i) => {
r[i] = Array(24).fill(0);
value.forEach(o => {
let start = getHours(o.from);
const end = getHours(o.to);
while (start <= end) {
r[i][start] = 1;
start++;
}
})
return r;
}, []);
this.rowTable.forEach((el, i) => {
el.items = result[i];
el.active = false;
})
}
}
我的尝试,但我不知道我是否朝着正确的方向前进。请帮忙
it("should loading Time"), () => {
const timetableMock = new Map<number, Array<from: string to: string>>()
timetableMock.set(0, [{ from: '00:00', to: '23:00' }]);
component.loadingTime = () => {};
const onSaveSpy = spyOn(component, "loadingTime")
component.loadingTime();
expect(onSaveSpy).toEqual([........I don't know what to enter here]);
}
【问题讨论】:
-
您无法检查返回的值。但是你可以检查
getHours是否被调用。 -
测试行为。用户应该看到什么?不要模拟你应该测试的部分 - 你的测试目前绝对没有意义,因为你用无操作实现替换方法,然后监视该实现,然后调用间谍并断言。 ..间谍被召唤了?真正的实现是如何涉及的?
标签: javascript angular typescript jestjs