更改 tkinter 中按钮的颜色答案

【问题标题】：Changing colour of buttons in tkinter更改 tkinter 中按钮的颜色
【发布时间】：2014-02-22 20:34:24
【问题描述】：

在尝试制作电梯模拟器时，我遇到了一个问题。有4部电梯，按楼层号应该变成红色。这适用于 1 部电梯中的 1 个“面板”，但不适用于每部电梯中的 1 个“面板”。这是我的代码：

def floorChooserButtons( self, eleNum, floors, yStart, yEnd, xStart, xEnd):
    self.Buttons1 = [i for i in range(41)]
    self.Buttons2 = [i for i in range(41)]
    self.Buttons3 = [i for i in range(41)]
    self.Buttons4 = [i for i in range(41)]
    if(eleNum is 1):
        xPos = xStart
        yPos = yStart
        for floor in floors:
            if(yPos == yEnd):
                xPos = xPos + 1
                yPos = yStart
            if(xPos == xEnd-1):
                yPos = yStart+2
            self.Buttons1[floor] = tk.Button(self, width=3, text=floor, 
                command = lambda f=floor: self.chooser(f, eleNum))
            self.Buttons1[floor].grid(row=xPos, column =yPos)
            yPos = yPos + 1
    elif(eleNum is 2):
        xPos = xStart
        yPos = yStart
        for floor in floors:
            if(yPos == yEnd):
                xPos = xPos + 1
                yPos = yStart
            if(xPos == xEnd-1):
                yPos = yStart+2
            self.Buttons2[floor] = tk.Button(self, width=3, text=floor, 
                command = lambda f=floor: self.chooser(f, eleNum))
            self.Buttons2[floor].grid(row=xPos, column =yPos)
            yPos = yPos + 1
    elif(eleNum is 3):
        xPos = xStart
        yPos = yStart
        for floor in floors:
            if(yPos == yEnd):
                xPos = xPos + 1
                yPos = yStart
            if(xPos == xEnd-1):
                yPos = yStart+2
            self.Buttons3[floor] = tk.Button(self, width=3, text=floor, 
                command = lambda f=floor: self.chooser(f, eleNum))
            self.Buttons3[floor].grid(row=xPos, column =yPos)
            yPos = yPos + 1
    elif(eleNum is 4):
        xPos = xStart
        yPos = yStart
        for floor in floors:
            if(yPos == yEnd):
                xPos = xPos + 1
                yPos = yStart
            if(xPos == xEnd-1):
                yPos = yStart+2
            self.Buttons4[floor] = tk.Button(self, width=3, text=floor, 
                command = lambda f=floor: self.chooser(f, eleNum))
            self.Buttons4[floor].grid(row=xPos, column =yPos)
            yPos = yPos + 1
        self.QUIT = tk.Button(self, text="QUIT", fg="red",
            command=root.destroy).grid(row = xPos, column = yPos)


def chooser(self, index, eleNum):
    print("Number", index, "pressed in elevator", eleNum)
    if eleNum is 1:
        self.Buttons1[index].configure(bg="red")
    if eleNum is 2:
        self.Buttons2[index].configure(bg="red")
    if eleNum is 3:
        self.Buttons3[index].configure(bg="red")
    if eleNum is 4:
        self.Buttons4[index].configure(bg="red")

eleNum 为电梯编号，1-4 yStart、yEnd、xStart、xEnd都用于布局。

任何帮助都会令人震惊。谢谢

【问题讨论】：

这是错误的代码。
@hd1 这只是由于stackoverflow，我试图缩进它并且它不允许我这样做。它在我的代码中正确缩进。
@MartynRushton：你是什么意思它不允许你？当然会的。用空格替换所有选项卡，插入代码，突出显示它，然后单击{} 按钮。如果您希望人们努力回答您的问题，那么您应该努力提出问题。
好吧，原来我搞砸了……现在完成了=D

标签： python button tkinter

【解决方案1】：

您可以通过多种方式更改按钮的颜色

b = Button(background = 'red')
b.config(background = 'red')
b.configure(background = 'red')
b['background'] = 'red'

b = Button(bg = 'red')
b.config(bg = 'red')
b.configure(bg = 'red')
b['bg'] = 'red'

您可以使用foreground 或fg 更改字体颜色

【讨论】：