【发布时间】:2019-09-02 12:47:03
【问题描述】:
我正在做这个项目,但我被困住了。我有一个表单,在表单上,我有一个下一步按钮和上一个按钮:
在我的HouseList 类中,我有这段代码,我想做的是创建一个获取下一个房子的方法和另一个到达上一个房子的方法。我已经尝试了这么久。
public HouseList()
{
housesList = new List<House>();
housesList.Add(new House()
{
Address = "35 Twin Oaks",
City = "Glendale",
Zip = "MDN6L3",
AskingPrice = "328,743.00",
PictureFile = "",
AveragePrice = "490,747.80",
Total = "2,453,739.00"
});
housesList.Add(new House()
{
Address = "35 Helen Drive",
City = "OakDale",
Zip = "G6L5M4",
AskingPrice = "455,899.00",
PictureFile = "",
AveragePrice = "490,747.80",
Total = "2,453,739,00"
});
housesList.Add(new House()
{
Address = "4 RiverBank Rd",
City = "Brampton",
Zip = "L9H4L2",
AskingPrice = "699,999.00",
PictureFile = "",
AveragePrice = "490,747.80",
Total = "2,453,739,00"
});
}
public List<string> NextHouse()
{
List<string> house = new List<string>();
foreach (House h in housesList)
{
int index = 0;
string conv = Convert.ToString(index);
if (conv == house[1])
{
conv = house[1];
}
}
return house;
}
【问题讨论】:
-
或者将List设置为BindingSource的DataSource,将所有控件绑定到BindingSource。之后,一切都是自动的。