我需要在矩形中添加文本，我该怎么做？

Question

我需要在按钮中绘制文本，在我的程序中可以将其视为四个较小的矩形，除此之外，我还需要在标题上绘制文本。我不确定如何做到这一点，因为我的程序结构与我见过的其他程序不同。

关注了其他问题，以及他们收到的试图影响我的答案。

import pygame
import sys

def main():
    pygame.init()
    clock = pygame.time.Clock()
    fps = 60
    size = [700, 600]
    bg = [255, 255, 255]
    font = pygame.font.Font('freesansbold.ttf', 32) 

    screen = pygame.display.set_mode(size)

    black = (0, 0, 0)

    button = pygame.Rect(400, 400, 250, 125) 
    button2 = pygame.Rect(50, 400, 250, 125)
    button3 = pygame.Rect(400, 250, 250, 125)
    button4 = pygame.Rect(50, 250, 250, 125)

    while True:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                return False


            if event.type == pygame.MOUSEBUTTONDOWN:
                mouse_pos = event.pos  # gets mouse position

                # checks if mouse position is over the button

                if button.collidepoint(mouse_pos):
                    # prints current location of mouse
                    print('Instructions'.format(mouse_pos))

                if button2.collidepoint(mouse_pos):
                    # prints current location of mouse
                    print('Controls'.format(mouse_pos))

                if button3.collidepoint(mouse_pos):
                    # prints current location of mouse
                    print('Information'.format(mouse_pos))

                if button4.collidepoint(mouse_pos):
                    # prints current location of mouse
                    print('Start Game'.format(mouse_pos))


        screen.fill(bg)

        pygame.draw.rect(screen, black, (button))  # draw button
        pygame.draw.rect(screen, black, (button2))
        pygame.draw.rect(screen, black, (button3))
        pygame.draw.rect(screen, black, (button4))
        pygame.draw.rect(screen, black, (50, 25, 600, 200))

        pygame.display.update()
        clock.tick(fps)

    pygame.quit()
    sys.exit


if __name__ == '__main__':
    main()

我希望按钮上有文字，所以以后当我点击它们时，它们会打开一个新窗口。

Answer 1

如果你想使用pygame.font，你必须通过pygame.font.Font.render来渲染文本：

例如

 red = (255, 0, 0)
 button = pygame.Rect(400, 400, 250, 125) 
 text = font.render("button 1", True, red)

结果是一个pygame.Surface，可以是.blit到矩形按钮区域的中心：

pygame.draw.rect(screen, black, button) 
textRect = text.get_rect()
textRect.center = button.center
screen.blit(text, textRect)

---

另一种选择是使用pygame.freetype：

例如

import pygame.freetype

ft_font = pygame.freetype.SysFont('Times New Roman', 32)

通过pygame.freetype.Font.render_to将文本直接渲染到屏幕上

text2 = "button 2"
textRect2 = ft_font.get_rect("button 2")

pygame.draw.rect(screen, black, button2)
textRect2.center = button2.center
ft_font.render_to(screen, textRect2, text2, red)