为什么我收到此错误？GuzzleHttp\Exception\ClientException 并带有消息“客户端错误：`401 Unauthorized`

Question

我正在尝试在我的项目中实施 Paypal Sandbox。我在app 文件夹中创建了一个trait：

use GuzzleHttp\Client;

trait ConsumesExternalServices
{
    public function makeRequest(
        $method,
        $requestUrl,
        $queryParams = [],
        $formParams = [],
        $headers = [],
        $isJsonRequest=false
    ) {
        $client = new Client([
            'base_uri' => $this->baseUri,
        ]);

        if (method_exists($this, 'resolveAuthorization')) {
            $this->resolveAuthorization($queryParams, $formParams, $headers);
        }

        $response = $client->request($method, $requestUrl, [
            $isJsonRequest ? 'json' : 'form_params' => $formParams,
            'headers' => $headers,
            'query' => $queryParams,
        ]);

        $response = $response->getBody()->getContents();
        if (method_exists($this, 'decodeResponse')) {
            $response = $this->decodeResponse($response);
        }

        return $response;
    }
}

我还创建了 Paypal 服务：

use App\Traits\ConsumesExternalServices;

class PaypalServices
{
    use ConsumesExternalServices;

    protected $baseUri;
    protected $clientId;
    protected $clientSecret;

    public function __construct()
    {
        $this->baseUri = config('services.paypal.base_uri');
        $this->clientId = config('services.paypal.client_id');
        $this->clientSecret = config('services.paypal.client_secret');
    }

    public function resolveAuthorization(&$queryParams, &$formParams, &$headers)
    {
        $headers['Authorization']=$this->resolveAccessToken();
    }

    public function decodeResponse($response)
    {
        return json_decode($response);
    }

    public function resolveAccessToken()
    {
        $credentials = base64_encode("{$this->clientId} : {$this->clientSecret}");
  
        return "Basic {$credentials}";
    }
}

我正在尝试将我的沙盒帐户与我的项目集成，但每当我使用 tinker 并尝试发出请求时，我都会收到以下错误：

Psy Shell v0.10.8 (PHP 7.4.15 — cli) by Justin Hileman
>>> $paypal=new App\Services\PaypalServices;
=> App\Services\PaypalServices {#3473}
>>> $paypal->makeRequest('GET','v1/invoicing/invoices');

GuzzleHttp\Exception\ClientException with message 'Client error: `GET https://api-m.sandbox.paypal.com/v1/invoicing/invoices` resulted in a `401 Unauthorized` response:{"error":"invalid_client","error_description":"Client Authentication failed"}

我不知道是什么问题。 Laravel 版本是 8，我使用的是 Paypal Malaysia 帐户。

我在.env文件中提到过：

PAYPAL_BASE_URI=https://api-m.sandbox.paypal.com
PAYPAL_CLIENT_ID=
PAYPAL_CLIENT_SECRET=

在我的config/servies.php 文件中：

'paypal' => [
    'base_uri' => env('PAYPAL_BASE_URI'),
    'client_id' => env('PAYPAL_CLIENT_ID'),
    'client_secret' => env('PAYPAL_CLIENT_SECRET')
],

Answer 1

您使用的是什么客户端 ID？是沙盒吗？如果您使用将 base_uri 设置为沙盒的实时版本，则会出现 401 错误。您需要来自REST apps 的有效客户端 ID + 密码，用于您正在测试的环境。如果您仍然有问题，请在那里创建一个新的 REST 应用程序，并确保您正确地复制粘贴。