如何使用 Java 处理 Selenium WebDriver 中的弹出窗口

Question

我想在 rediff.com 中处理登录部分，但下面的代码对此不起作用：

driver.get("http://www.rediff.com/");
WebElement sign = driver.findElement(By.xpath("//html/body/div[3]/div[3]/span[4]/span/a"));
sign.click();
String myWindowHandle = driver.getWindowHandle();
driver.switchTo().window(myWindowHandle);
WebElement email_id= driver.findElement(By.xpath("//*[@id='signin_info']/a[1]"));
email_id.sendKeys("hi");

如果myWindowHandle不是正确的字符串，那么请告诉我如何获取弹出窗口名称，因为我找不到弹出窗口的名称。

Answer 1

要切换到弹出窗口，您需要使用getWindowHandles() 并遍历它们。

在您的代码中，您使用的是getWindowHandle()，它将为您提供父窗口本身。

String parentWindowHandler = driver.getWindowHandle(); // Store your parent window
String subWindowHandler = null;

Set<String> handles = driver.getWindowHandles(); // get all window handles
Iterator<String> iterator = handles.iterator();
while (iterator.hasNext()){
    subWindowHandler = iterator.next();
}
driver.switchTo().window(subWindowHandler); // switch to popup window

// Now you are in the popup window, perform necessary actions here

driver.switchTo().window(parentWindowHandler);  // switch back to parent window

Answer 2

我找到了上述程序的解决方案，其目标是登录http://rediff.com

public class Handle_popupNAlert
{
    public static void main(String[] args ) throws InterruptedException
    {
        WebDriver driver= new FirefoxDriver(); 
        driver.get("http://www.rediff.com/");
        WebElement sign = driver.findElement(By.xpath("//html/body/div[3]/div[3]/span[4]/span/a"));
        sign.click();

        Set<String> windowId = driver.getWindowHandles();    // get  window id of current window
        Iterator<String> itererator = windowId.iterator();   

        String mainWinID = itererator.next();
        String  newAdwinID = itererator.next();

        driver.switchTo().window(newAdwinID);
        System.out.println(driver.getTitle());
        Thread.sleep(3000);
        driver.close();

        driver.switchTo().window(mainWinID);
        System.out.println(driver.getTitle());
        Thread.sleep(2000);

        WebElement email_id= driver.findElement(By.xpath("//*[@id='c_uname']"));
        email_id.sendKeys("hi");
        Thread.sleep(5000);

        driver.close();
        driver.quit();
    }  
}

Answer 3

您可以处理弹出窗口或警告框：

Alert alert = driver.switchTo().alert();
alert.accept();

您也可以拒绝提醒框：

Alert alert = driver.switchTo().alert();
alert().dismiss();

Answer 4

当您收到任何网络浏览器弹出警报消息框时，您可以在代码中使用以下代码。

// Accepts (Click on OK) Chrome Alert Browser for RESET button.

Alert alertOK = driver.switchTo().alert();
alertOK.accept();



//Rejects (Click on Cancel) Chrome Browser Alert for RESET button.

Alert alertCancel = driver.switchTo().alert();
alertCancel.dismiss();

Answer 5

不要让情况变得复杂。如果可用，请使用ID。

driver.get("http://www.rediff.com");
WebElement sign = driver.findElement(By.linkText("Sign in"));
sign.click();
WebElement email_id= driver.findElement(By.id("c_uname"));
email_id.sendKeys("hi");

Answer 6

当 Firefox 的屏幕上弹出 toastr 消息时。下面的标签显示在火虫中。

<div class="toast-message">Invalid Credentials, Please check Password</div>.

我当时截图了。 并在 selenium java 代码中做了以下更改。

String alertText = "";
WebDriverWait wait = new WebDriverWait(driver, 5);
wait.until(ExpectedConditions.visibilityOfElementLocated(By.className("toast-message")));
WebElement toast1 = driver.findElement(By.className("toast-message"));  
alertText = toast1.getText();
System.out.println( alertText);

我的 toastr 弹出问题得到了解决。

Answer 7

String parentWindowHandler = driver.getWindowHandle(); // Store your parent window
String subWindowHandler = null;

Set<String> handles = driver.getWindowHandles(); // get all window handles
Iterator<String> iterator = handles.iterator();

subWindowHandler = iterator.next();

driver.switchTo().window(subWindowHandler); // switch to popup window

// Now you are in the popup window, perform necessary actions here

driver.switchTo().window(parentWindowHandler);  // switch back to parent window

Answer 8

       //get the main handle and remove it
       //whatever remains is the child pop up window handle

       String mainHandle = driver.getWindowHandle();
       Set<String> allHandles = driver.getWindowHandles();
       Iterator<String> iter = allHandles.iterator();
       allHandles.remove(mainHandle);
       String childHandle=iter.next();

Answer 9

public void Test(){

     WebElement sign = fc.findElement(By.xpath(".//*[@id='login-scroll']/a"));
        sign.click();
        WebElement LoginAsGuest=fc.findElement(By.xpath(".//*[@id='guest-login-option']"));
        LoginAsGuest.click();
        WebElement email_id= fc.findElement(By.xpath(".//*[@id='guestemail']"));
        email_id.sendKeys("ankushdeoladore@gmail.com");
        WebElement ContinueButton=fc.findElement(By.xpath(".//*[@id='contibutton']"));
        ContinueButton.click();

}