【发布时间】：2014-07-26 23:19:47
【问题描述】：
好的，在阅读一些教程时，我在尝试学习 XmlSerializer 时遇到了障碍。我已遵循所有推荐的步骤，但我的程序没有返回任何内容，或者返回 null。我创建了一个 XML 文件如下：
<?xml version='1.0' encoding='UTF-8' ?>
<WeeklyJobs>
<DailyJobs Date = "02/03/2012"/>
<DailyJobs Date = "02/04/2012" TotalJobs = "2">
<Jobs>
<Job JobName = "Job Name" Description = "Description"/>
<Job JobName = "Job Name" Description = "Description"/>
</Jobs>
</DailyJobs>
<DailyJobs Date = "02/05/2012" TotalJobs = "1">
<Jobs>
<Job JobName = "Job Name" Description = "Description"/>
</Jobs>
</DailyJobs>
<DailyJobs Date = "02/06/2012" TotalJobs = "2">
<Jobs>
<Job JobName = "Job Name" Description = "Description"/>
<Job JobName = "Job Name" Description = "Description"/>
</Jobs>
</DailyJobs>
<DailyJobs Date = "02/07/2012"/>
<DailyJobs Date = "02/08/2012" TotalJobs = "2">
<Jobs>
<Job JobName = "Job Name" Description = "Description"/>
<Job JobName = "Job Name" Description = "Description"/>
</Jobs>
</DailyJobs>
</WeeklyJobs>
然后我使用 xsd.exe 生成 .xsd 文件，即：
<?xml version="1.0" encoding="utf-8"?>
<xs:schema id="WeeklyJobs" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">
<xs:element name="WeeklyJobs" msdata:IsDataSet="true" msdata:UseCurrentLocale="true">
<xs:complexType>
<xs:choice minOccurs="0" maxOccurs="unbounded">
<xs:element name="DailyJobs">
<xs:complexType>
<xs:sequence>
<xs:element name="Jobs" minOccurs="0" maxOccurs="unbounded">
<xs:complexType>
<xs:sequence>
<xs:element name="Job" minOccurs="0" maxOccurs="unbounded">
<xs:complexType>
<xs:attribute name="JobName" type="xs:string" />
<xs:attribute name="Description" type="xs:string" />
</xs:complexType>
</xs:element>
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:sequence>
<xs:attribute name="Date" type="xs:string" />
<xs:attribute name="TotalJobs" type="xs:string" />
</xs:complexType>
</xs:element>
</xs:choice>
</xs:complexType>
</xs:element>
</xs:schema>
创建架构后，我再次使用 xsd.exe 为我自动生成类：
/// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "", IsNullable = false)]
public partial class WeeklyJobs
{
private WeeklyJobsDailyJobs[] itemsField;
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute("DailyJobs", Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
public WeeklyJobsDailyJobs[] Items
{
get
{
return this.itemsField;
}
set
{
this.itemsField = value;
}
}
}
/// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class WeeklyJobsDailyJobs
{
private WeeklyJobsDailyJobsJobsJob[][] jobsField;
private string dateField;
private string totalJobsField;
/// <remarks/>
[System.Xml.Serialization.XmlArrayAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
[System.Xml.Serialization.XmlArrayItemAttribute("Job", typeof(WeeklyJobsDailyJobsJobsJob), Form = System.Xml.Schema.XmlSchemaForm.Unqualified, IsNullable = false)]
public WeeklyJobsDailyJobsJobsJob[][] Jobs
{
get
{
return this.jobsField;
}
set
{
this.jobsField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string Date
{
get
{
return this.dateField;
}
set
{
this.dateField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string TotalJobs
{
get
{
return this.totalJobsField;
}
set
{
this.totalJobsField = value;
}
}
}
/// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class WeeklyJobsDailyJobsJobsJob
{
private string jobNameField;
private string descriptionField;
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string JobName
{
get
{
return this.jobNameField;
}
set
{
this.jobNameField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string Description
{
get
{
return this.descriptionField;
}
set
{
this.descriptionField = value;
}
}
}
在此之后，我将 .CS 文件添加到我的项目中，并创建了一个带有 TextBox 的简单 winform，以便在我反序列化一些 xml 后显示一些数据。就像我说的那样，程序启动了，TextBox 中没有显示任何内容，也没有抛出异常。这是我的winform：
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
public string getExample()
{
XmlSerializer serializer = new XmlSerializer(typeof(WeeklyJobs));
WeeklyJobs jobs;
string xml = @"<?xml version = ""1.0""?>"
+ @"<WeeklyJobs>"
+ @"<DailyJobs Date = ""02/03/2012""/>"
+ @"<DailyJobs Date = ""02/04/2012"" TotalJobs = ""2"">"
+ @"<Jobs>"
+ @"<Job JobName = ""Job Name"" Description = ""Description""/>"
+ @"<Job JobName = ""Job Name"" Description = ""Description""/>"
+ @"</Jobs>"
+ @"</DailyJobs>"
+ @"</WeeklyJobs>";
// Create an XmlTextReader
using (XmlReader reader = XmlReader.Create(new StringReader(xml)))
{
jobs = (WeeklyJobs)serializer.Deserialize(reader);
}
return jobs.Items[0].Date;
}
private void Form1_Load(object sender, EventArgs e)
{
textBox1.Text = getExample();
}
}
我有更多简单的 xml 示例可以工作，但第二次尝试向我的 xml 添加一些复杂性时我失败了。我必须弄清楚如何使用我在这里拥有的 xml。感谢您的帮助！谢谢大家！
【问题讨论】：
-
根据我的经验，了解 xml 序列化如何工作的最佳方法是创建该类型的实例并对其进行序列化，以查看结果的样子。您可能会在测试中看到 xml 字符串中遗漏的一些重要内容。
-
好吧，我只是想重现这个，似乎 XmlSerialization 代码有问题（错误 CS0030：无法将类型“DeleteMe.WeeklyJobsDailyJobsJobsJob[]”转换为“DeleteMe.WeeklyJobsDailyJobsJobsJob”/错误 CS0029：无法将类型“DeleteMe.WeeklyJobsDailyJobsJobsJob”隐式转换为“DeleteMe.WeeklyJobsDailyJobsJobsJob[]”）。我试图弄清楚。但我还要说，我通常的做法是手动编写我自己的类。如果我能找到问题，我会再发表评论。
标签： c# xml deserialization xmlreader