【发布时间】:2011-09-26 08:44:45
【问题描述】:
我有这个代码:
#include <fstream>
#include <iostream>
using namespace std;
class Student
{
public:
char FullName[40];
char CompleteAddress[120];
char Gender;
double Age;
bool LivesInASingleParentHome;
};
int main()
{
Student one;
strcpy(one.FullName, "Ernestine Waller");
strcpy(one.CompleteAddress, "824 Larson Drv, Silver Spring, MD 20910");
one.Gender = 'F';
one.Age = 16.50;
one.LivesInASingleParentHome = true;
ofstream ofs("fifthgrade.ros", ios::binary);
ofs.write((char *)&one, sizeof(one));
Student three;
strcpy(three.FullName, "three Waller");
strcpy(three.CompleteAddress, "three 824 Larson Drv, Silver Spring, MD 20910");
three.Gender = 'M';
three.Age = 17;
three.LivesInASingleParentHome = true;
//ofstream ofs("fifthgrade.ros", ios::binary);
ofs.write((char *)&three, sizeof(three));*/
Student two;
ifstream ifs("fifthgrade.ros", ios::binary);
while(!(ifs.eof())){
ifs.read((char *)&two, sizeof(two));
cout << "Student Information\n";
cout << "Student Name: " << two.FullName << endl;
cout << "Address: " << two.CompleteAddress << endl;
if( two.Gender == 'f' || two.Gender == 'F' )
cout << "Gender: Female" << endl;
else if( two.Gender == 'm' || two.Gender == 'M' )
cout << "Gender: Male" << endl;
else
cout << "Gender: Unknown" << endl;
cout << "Age: " << two.Age << endl;
if( two.LivesInASingleParentHome == true )
cout << "Lives in a single parent home" << endl;
else
cout << "Doesn't live in a single parent home" << endl;
cout << "\n";
}
return 0;
}
当我从文件中读取时,最后一个对象打印两次。我该怎么办?
【问题讨论】:
-
这样的书写结构是不可移植的。它依赖于特定于主机的打包、浮点表示和各种丑陋的东西,并且在结构中包含漏洞。您应该以序列化、规范化的形式编写它。
-
@Seth:你是对的。我认为公平地说,这很可能是家庭作业,这对于示例来说是可以的
-
@sehe:在他们有机会在更严重的项目中犯这样的错误之前对他们进行培训。
标签: c++ file serialization object