【发布时间】:2017-07-13 18:58:24
【问题描述】:
我有这个代码
@FXML
private ToggleButton tb1;
@FXML
private ToggleButton tb2;
@FXML
ToggleGroup group = new ToggleGroup();
String cpuLoad1 ="D:/myWorkspace/TestAttacks/input_folder/app_debug.apk";
String cpuLoad2 = "D:/myWorkspace/TestAttacks/input_folder/cpuLoad1.apk";
@FXML
private void onToggleClick(){
tb1.setUserData(cpuLoad1);
tb1.setToggleGroup(group);
tb2.setUserData(cpuLoad2);
tb2.setToggleGroup(group);
ChangeListener<Toggle> cLt = new ChangeListener<Toggle>(){
public void changed(ObservableValue<? extends Toggle> ov,
Toggle toggle, Toggle new_toggle){
if (new_toggle != null){
System.out.println(group.getSelectedToggle().getUserData().toString());
}else{
System.out.println("hello no");
}
}
};
group.selectedToggleProperty().addListener(cLt);
}
虽然我仍然没有使用用户数据,但问题是每当我单击切换按钮时,我都会按递增顺序获得所需的输出。
这是输出:
hello no //click2
D:/myWorkspace/TestAttacks/input_folder/app_debug.apk //click3
D:/myWorkspace/TestAttacks/input_folder/app_debug.apk
hello no //click4
hello no
hello no
D:/myWorkspace/TestAttacks/input_folder/app_debug.apk //click5
D:/myWorkspace/TestAttacks/input_folder/app_debug.apk
D:/myWorkspace/TestAttacks/input_folder/app_debug.apk
D:/myWorkspace/TestAttacks/input_folder/app_debug.apk
hello no //click6
hello no
hello no
hello no
hello no
D:/myWorkspace/TestAttacks/input_folder/app_debug.apk //click7
D:/myWorkspace/TestAttacks/input_folder/app_debug.apk
D:/myWorkspace/TestAttacks/input_folder/app_debug.apk
D:/myWorkspace/TestAttacks/input_folder/app_debug.apk
D:/myWorkspace/TestAttacks/input_folder/app_debug.apk
D:/myWorkspace/TestAttacks/input_folder/app_debug.apk
第一次点击我什么都没有。
从第二次点击我开始得到这种输出。谁能解释这种行为并为此提供解决方案?
【问题讨论】:
标签: java javafx listener togglebutton