【问题标题】:Golang Dijkstra goroutinesGolang Dijkstra 协程
【发布时间】:2022-01-06 09:28:44
【问题描述】:

所以基本上我需要使用 goroutine 做一个 Dijkstra 程序。

除了 goroutine 有一点问题外,我基本上什么都做了。由于它是 Dijkstra 算法,因此我使用一个函数来查找从给定节点到所有其他节点的最短路径。 goroutine 必须帮助我找到从 n 到 n 节点的最短路径,如下面的代码所示。

//This function will get us all the shortest paths from all the nodes to all the other nodes
//list []Edge here is our list containing all the characteristics given by the .txt file
//nodes []int gives us all the nodes in our graph
//map[int]map[int][]int is all the results for the paths for e.g {1:{2:[1 2](the paths that it took) 3:[1 3]...} 2:{1:{2 1}...}...}
//map[int]map[int]int is all the distances for the different paths for e.g {1:{2:1 3:2 4:3...},2...}
func Dijkstra(list []Edge, nodes []int) (map[int]map[int][]int, map[int]map[int]int) {
    var wg sync.WaitGroup // Waitgroup so that we won't get some things done before all the goroutines are done
    dijk := make(map[int]map[int][]int)
    distance := make(map[int]map[int]int)
    //start := time.Now()
    neighbors := getAllNeighbors(list, nodes)
    //fmt.Print(neighbors)
    //We get all the neighbors for every node we have in our graph
    //{1:[{1 2 1},{1 3 2}],B:...}
    for _, node := range nodes { //for every node we have we are going to get the shortest path to all the other nodes
        var routes map[int][]int
        var distances map[int]int

        wg.Add(1)   //We add our next goroutine in the waitgroup
        go func() { //goroutine
            routes, distances = oneDijkstra(node, &wg, list, nodes, neighbors) //function that will give us the shortes path from the node to other nodes of the list
        }()
        wg.Wait() //We wait until the waitgroup is empty to do the rest of the code
        //We can't add routes to our dijk if it's not completed
        dijk[node] = routes
        //for this node, we add the other nodes with the way to take to have the shortest path with them
        distance[node] = distances
        //for this node, we add for every other node the cost it takes for the shortest path
    }
    //fmt.Print(time.Since(start))
    return dijk, distance
}

问题在于这段代码在其实际状态下并不能很好地使用 goroutines。我想知道我应该把它放在哪里以使我的结果更快(因为这里就像没有 goroutines)。提前感谢任何可以给我一些解决方案的人。

【问题讨论】:

    标签: go parallel-processing dijkstra goroutine


    【解决方案1】:

    我认为将您的等待移至 for 循环之后并将结果直接分配给您的切片将满足您的需求。

    for _, node := range nodes { //for every node we have we are going to get the shortest path to all the other nodes
            wg.Add(1)   //We add our next goroutine in the waitgroup
            go func() { //goroutine
               defer wg.Done();
               dijk[node] , distance[node] = oneDijkstra(node, &wg, list, nodes, neighbors) //function that will give us the shortes path from the node to other nodes of the list
            }()
        }
        wg.wait();
        
    

    【讨论】:

    【解决方案2】:

    Dijkstra 函数没有同时处理节点的主要原因是因为您等待 goroutine 在循环内完成(使用wg.Wait())。本质上,每个节点不是同时处理的。

    一种可能的解决方案:

    首先,修改您的 oneDijkstra 函数以接收您将向其发送数据的通道(数据只是包含所有信息的结构)。

    func ondeDijkstra(node int, wg *sync.WaitGroup, list []Edge, nodes []int, neighbours []Edge, dataCh chan<- data){
       defer wg.Done()
       //your calculations
       // ...
       datach <- data{node, routes, distances}
    }
    

    接下来,在Dijkstra 函数中,您需要更改一些内容。

    首先,启动一个从dataCh 通道读取并添加到地图的goroutine。我个人更喜欢这个解决方案,因为它避免了maps being modified concurrently。 接下来,遍历节点,为每个节点启动一个 goroutine,并在循环后等待一切完成。

    func Dijkstra(list []Edge, nodes []int) (map[int]map[int][]int, map[int]map[int]int) {
        var wg sync.WaitGroup 
        datach := make(chan data)
        done := make(chan bool)
        dijk := make(map[int]map[int][]int)
        distance := make(map[int]map[int]int)
        neighbors := getAllNeighbors(list, nodes)
    
        //start a goroutine that will read from the data channel
        go func(){
          for d := range dataCh {
            dijk[d.node] = d.routes
            distance[d.node] = d.distances
          }
          done <- true //this is used to wait until all data has been read from the channel
        }()
        
        wg.Add(len(nodes))
        for _, node := range nodes {  
            go oneDijkstra(node, &wg, list, nodes, neighbors, dataCh)
        }
        
        wg.Wait()
        close(dataCh) //this closes the dataCh channel, which will make the for-range loop exit once all the data has been read
        <- done //we wait for all of the data to get read and put into maps
    
        return dijk, distance
    }
    

    【讨论】:

    • 非常感谢它成功了!
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