WebSocket 握手期间出错：PHP 的“Sec-WebSocket-Accept”标头值不正确

Question

我已经用 PHP 编写了 websocket 服务器/客户端，它在 2 年内为我工作。现在不行了，说：Error during WebSocket handshake: Incorrect 'Sec-WebSocket-Accept' header value

我的客户端代码基本上是这样的：

socket = new WebSocket("ws://<?= EVENT_SERVER_ADDR ?>:"+EVENT_SERVER_PORT+"<?= EVENT_SERVER_WWW_PATH ?>");

PHP 服务器端代码是这样的：

list ($resource, $host, $connection, $version, $origin, $key, $protocol, $upgrade) = $this->getheaders ($buffer);

$this->log ("Handshaking...");
$reply  = 
    "HTTP/1.1 101 Switching Protocols\r\n" .
    "Upgrade: {$upgrade}\r\n" .
    "Connection: {$connection}\r\n" .
    "Sec-WebSocket-Version: {$version}\r\n" .
    "Sec-WebSocket-Origin: {$origin}\r\n" .
    "Sec-WebSocket-Location: ws://{$host}{$resource}\r\n" .
    "Sec-WebSocket-Accept: " . $this->calcKey ($key) . "\r\n";
if ($protocol)
    $reply .= "Sec-WebSocket-Protocol: $protocol\r\n";
$reply .=   "\r\n";

// Closes the handshake
socket_write ($user->socket, $reply, strlen ($reply));

function calcKey ($key) {
    // Constant string as specified in the ietf-hybi-17 draft
    $key .= "258EAFA5-E914-47DA-95CA-C5AB0DC85B11";
    $key = sha1 ($key, true);
    // $key = pack ('H*', $key); // should I uncomment this line?
    $key = base64_encode ($key);

    return $key;
}

function getheaders ($buffer) {
    $resource = $host = $connection = $version = $origin = $key = $protocol = $upgrade = null;

    preg_match ('#GET (.*?) HTTP#', $buffer, $match) && $resource = $match[1];
    preg_match ("#Host: (.*?)\r\n#", $buffer, $match) && $host = $match[1];
    preg_match ("#Connection: (.*?)\r\n#", $buffer, $match) && $connection = $match[1];
    preg_match ("#Sec-WebSocket-Version: (.*?)\r\n#", $buffer, $match) && $version = $match[1];
    preg_match ("#Origin: (.*?)\r\n#", $buffer, $match) && $origin = $match[1];
    preg_match ("#Sec-WebSocket-Key:\s*(.*?)\r\n#", $buffer, $match) && $key = $match[1];
    preg_match ("#Sec-WebSocket-Protocol:\s*(.*?)\r\n#", $buffer, $match) && $protocol = $match[1];
    preg_match ("#Upgrade: (.*?)\r\n#", $buffer, $match) && $upgrade = $match[1];

    return array ($resource, $host, $connection, $version, $origin, $key, $protocol, $upgrade);
}

有趣的是，这些人只是更改了标准，却没有保持旧代码正常运行，也没有在网上说任何话（我真的很努力地用谷歌搜索它）。有谁知道我的问题是什么？

Answer 1

所以我发现了问题所在。这就是缓冲区限制。

显然，变量$buffer 仅包含大约 4 KB 的数据，并且由于来自 dataTables 的 cookie，输入数据要多得多。 Sec-WebSocket-Key 标头毕竟是 cookie。所以$key每次都是空的，给错了Sec-WebSocket-Accept。

建议：更深入地调试。