【发布时间】:2018-05-09 12:10:50
【问题描述】:
我有一个包含一些类名的数组,该数组中的所有值都以数字结尾。我想要一个函数,当我给它一个数字时,它会搜索该数组,并检查每个值的最后 3 位数字,以找到匹配的数字并返回该匹配值。
所以可以说,我给它赋值200,它在数组中搜索并返回wi-owm-200。
我设法做到了,但它没有返回它。它确实找到了值,但是当它在函数之外时,它返回'undefined'。
这是我的代码:Fiddle
var owmIcon = ["wi-owm-200", "wi-owm-201", "wi-owm-202", "wi-owm-210", "wi-owm-211", "wi-owm-212", "wi-owm-221", "wi-owm-230", "wi-owm-231", "wi-owm-232", "wi-owm-300", "wi-owm-301", "wi-owm-302", "wi-owm-310", "wi-owm-311", "wi-owm-312", "wi-owm-313", "wi-owm-314", "wi-owm-321", "wi-owm-500", "wi-owm-501", "wi-owm-502", "wi-owm-503", "wi-owm-504", "wi-owm-511", "wi-owm-520", "wi-owm-521", "wi-owm-522", "wi-owm-531", "wi-owm-600", "wi-owm-601", "wi-owm-602", "wi-owm-611", "wi-owm-612", "wi-owm-615", "wi-owm-616", "wi-owm-620", "wi-owm-621", "wi-owm-622", "wi-owm-701", "wi-owm-711", "wi-owm-721", "wi-owm-731", "wi-owm-741", "wi-owm-761", "wi-owm-762", "wi-owm-771", "wi-owm-781", "wi-owm-800", "wi-owm-801", "wi-owm-802", "wi-owm-803", "wi-owm-804", "wi-owm-900", "wi-owm-901", "wi-owm-902", "wi-owm-903", "wi-owm-904", "wi-owm-905", "wi-owm-906", "wi-owm-957"];
var res = findOWMIcon("200");
console.log(res);
function findOWMIcon(num) {
$.each(owmIcon, function(key, value) {
var classNum = value.substr(value.length - 3);
if (parseInt(num, 10) === parseInt(classNum, 10)) {
console.log(value);
return value;
}
});
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
知道如何解决吗?所以我可以在函数之外得到找到的值吗?
【问题讨论】:
-
为什么会返回
word-200?数组中没有一个叫做那个的元素。 -
@Andy no
word-200只是示例。事实上它必须返回类似wi-owm-200的东西。会更新帖子。
标签: javascript jquery arrays scope return