将值从一种方法返回到另一种方法

Question

/* Assume as precondition that the list of players is not empty.
 * Returns the winning score, that is, the lowest total score.
 * @return winning score
 */
public int winningScore() {
    Player thePlayer = players.get(0);
    int result = thePlayer.totalScore();
    for (int i = 0; i < players.size(); i++){
        int p = players.get(i).totalScore();
        if (p < result) {
            result = players.get(i).totalScore();
        }
    }
    return result;
}

/* Returns the list of winners, that is, the names of those players
 * with the lowest total score.
 * The winners' names should be stored in the same order as they occur
 * in the tournament list.
 * If there are no players, return empty list.
 * @return list of winners' names
 */
public ArrayList<String> winners() {
    ArrayList<String> result = new ArrayList<String>();

    for (int i = 0; i < players.size(); i++)
        if (!players.isEmpty())
            return result;
}

正如它在 cmets 中所述，我试图在获胜者方法中返回winningScore() 结果，以便返回获胜者/获胜者的姓名。

我设法只返回了所有的获胜者，但我有点困惑是否应该从 winsScore() 方法调用它？

我知道我当前的代码对于获胜者来说是不正确的

任何正确方向的推动/提示将不胜感激！谢谢！

Answer 1

您要做的是在您的获胜者方法中找到所有具有获胜分数的玩家对象。

• 为此，您需要首先通过调用计算获胜分数 您的winningScore 方法。
• 接下来您会找到 totalScore 等于 之前计算的获胜分数。你想退回那些。

您的获胜者方法的生成代码将如下所示：

public ArrayList<String> winners() {
    ArrayList<String> result = new ArrayList<String>();

    int winningScore = winningScore();  

    for (int i = 0; i < players.size(); i++)
        if (players.get(i).totalScore() == winningScore)
            result.add(players.get(i).getName())

    return result;
}

如果您想简化代码，可以像这样使用ArrayList 迭代器将for 循环替换为循环，因为您不使用索引变量i：

for (Player player : players) {
    if (player.totalScore() == winningScore)
        result.add(player.getName())
}