如何将单元格值绑定到对象上的特定属性？

Question

我有一个DataTable，它在单元格级别使用以下类型填充：

public class GridCell
{
    public string Value { get; set}
    public Guid Id { get; set; }
}

我已将 DataTable 绑定到 WPF Toolkit DataGrid，但单元格显示为空。如何告诉DataGrid 在我的GridCell 类型的Value 属性中查找单元格内容？

绑定sn-p：

<DataGrid ItemsSource="{Binding SelectedItem.Table}" />

Answer 1

根据您问题中的有限信息，我猜您的数据表包含自定义类型的列，我不建议这样做，因为它会使您的代码更加复杂。但是，如果您决定采用这种方式，则可以实现自定义列类型来处理它。我没有尝试过，但这个链接看起来很有希望：Bind DataTable to WPF DataGrid using DataGridTemplateColumn Programatically

您也可以使用值转换器来实现相同的目标。下面的示例将列索引作为参数传递，但您也可以使用某种格式（例如，0-Value，表示第 0 列，属性值）传递您感兴趣的属性。

XAML：

<Window x:Class="GridCellDemo.Window1"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    xmlns:Controls="clr-namespace:Microsoft.Windows.Controls;assembly=WPFToolkit"
    xmlns:GridCellDemo="clr-namespace:GridCellDemo"
    Title="Window1" Height="300" Width="300">

    <Window.Resources>
        <GridCellDemo:CellConverter x:Key="CellConverter" />
    </Window.Resources>

    <Grid>
        <Controls:DataGrid ItemsSource="{Binding Data}" AutoGenerateColumns="False">
            <Controls:DataGrid.Columns>
                <Controls:DataGridTextColumn Header="Col 0" Binding="{Binding ., Converter={StaticResource CellConverter}, ConverterParameter=0}" />
                <Controls:DataGridTextColumn Header="Col 1" Binding="{Binding ., Converter={StaticResource CellConverter}, ConverterParameter=1}" />
            </Controls:DataGrid.Columns>
        </Controls:DataGrid>

    </Grid>
</Window>

后面的代码：

using System;
using System.Data;
using System.Windows;
using System.Windows.Data;

namespace GridCellDemo
{
    public partial class Window1 : Window
    {
        public Window1()
        {
            InitializeComponent();

            DataContext = this;
        }

        public DataTable Data
        {
            get
            {
                DataTable dt = new DataTable();
                dt.Columns.Add(new DataColumn("Col0", typeof(GridCell)));
                dt.Columns.Add(new DataColumn("Col1", typeof(GridCell)));

                DataRow row0 = dt.NewRow();
                dt.Rows.Add(row0);
                row0["Col0"] = new GridCell() { Value = "R0C0" };
                row0["Col1"] = new GridCell() { Value = "R0C1" };

                DataRow row1 = dt.NewRow();
                dt.Rows.Add(row1);
                row1["Col0"] = new GridCell() { Value = "R1C0" };
                row1["Col1"] = new GridCell() { Value = "R1C1" };

                return dt;
            }
        }
    }

    public class GridCell
    {
        public string Value { get; set;  }
        public Guid Id { get; set; }
    }

    public class CellConverter : IValueConverter
    {
        public object Convert(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
        {
            DataRowView drv = value as DataRowView;
            if (drv == null)
            {
                return string.Empty;
            }
            int columnIndex = int.Parse(parameter.ToString());
            GridCell gridCell = drv[columnIndex] as GridCell;
            return gridCell.Value;
        }

        public object ConvertBack(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
        {
            throw new NotImplementedException();
        }
    }
}

Answer 2

试试ItemsSource="{Binding Path=GridCellList}"。

<DataGrid ItemsSource="{Binding GridCellList}" AutoGenerateColumns="False">
    <DataGrid.Columns>
        <DataGridTextColumn Header="Value" Binding="{Binding Path=Value}" />
         <DataGridTextColumn Header="Guid" Binding="{Binding Path=Guid}" />
     </DataGrid.Columns>
 </DataGrid>