【发布时间】:2017-12-08 18:51:30
【问题描述】:
我一直在尝试为 Firebase 数据库提供一个平面数据结构(如推荐的那样),然后是一组规则来正确控制访问。我的示例试图演示如何锁定/允许访问跨不同组织的多租户数据库。
我的第一次尝试是这样的:
数据库结构:https://gist.github.com/peteski22/40b0a79a6854d7bb818919a5262f4a7e
{
"admins" : {
"8UnM6LIiZJYAHVdty6gzdD8oVI42" : true
},
"organizations": {
"-JiGh_31GA20JabpZBfc" : {
"name" : "Comp1 Ltd"
},
"-JiGh_31GA20JabpZBfd" : {
"name" : "company2 PLC"
}
},
"users" : {
"8UnM6LIiZJYAHVdty6gzdD8oVI42": {
"firstName" : "Peter",
"lastName" : "Piper",
"email" : "peter.piper@testtest.com",
"organization" : ""
},
"-JiGh_31GA20JabpZBfe" : {
"firstName" : "Joe",
"lastName" : "Blogs",
"email" : "joe.blogs@co1.com",
"organization" : "-JiGh_31GA20JabpZBfc"
},
"WgnHjk5D8xbuYeA7VDM3ngKwCYV2" : {
"firstName" : "test",
"lastName" : "user",
"email" : "test.user@google.com",
"organization" : "-JiGh_31GA20JabpZBfd"
}
},
"employees" : {
"-JiGh_31GA20JabpZBeb" : {
"organization" : "-JiGh_31GA20JabpZBfc",
"firstName" : "Johnny",
"lastName" : "Baggs",
"email" : "j.baggss@co1.com",
"employeeNumber" : "ASV123456"
},
"-JiGh_31GA20JabpZBec" : {
"organization" : "-JiGh_31GA20JabpZBfc",
"firstName" : "Maheswari",
"lastName" : "Sanjal",
"email" : "mahe.sanjal@co1.com",
"employeeNumber" : "ASV111111"
},
"-JiGh_31GA20JabpZBce" : {
"organization" : "-JiGh_31GA20JabpZBfd",
"firstName" : "Fedde",
"lastName" : "le Grande",
"email" : "fedde.grande@co2.com",
"employeeNumber" : "ASV111111"
}
}
}
数据库规则:https://gist.github.com/peteski22/b038d81641c1409cec734d187272eeba
{
"rules" : {
"admins" : {
".read" : "root.child('admins').hasChild(auth.uid)",
".write" : "root.child('admins').hasChild(auth.uid)"
},
"users" : {
"$user" : {
".read" : "data.child('organization').val() === root.child('users').child(auth.uid).child('organization').val()",
".write" : "root.child('admins').hasChild(auth.uid)"
}
},
"organizations" : {
"$organization" : {
".read" : "$organization === root.child('users').child(auth.uid).child('organization').val()",
".write" : "root.child('admins').hasChild(auth.uid)"
}
},
"employees" : {
"$employee" : {
".read" : "data.child('organization').val() === root.child('users').child(auth.uid).child('organization').val()",
".write" : "data.child('organization').val() === root.child('users').child(auth.uid).child('organization').val()"
}
}
}
}
但这里的问题似乎是我无法执行以下操作:
[GET] /employees
查看与登录用户属于同一组织的员工集合。
经过一番折腾,我在文档中读到了这个:https://firebase.google.com/docs/database/security/securing-data#rules_are_not_filters,如果你想以我的方式获取数据,我认为归结为“你做错了”。
回到画板,看完https://www.firebase.com/docs/web/guide/structuring-data.html/https://firebase.google.com/docs/database/web/structure-data
我对db结构和规则做了一些修改:
尝试 #2 结构:https://gist.github.com/peteski22/4593733bf54815393a443dfcd0f34c04
{
"admins" : {
"8UnM6LIiZJYAHVdty6gzdD8oVI42" : true
},
"organizations": {
"-JiGh_31GA20JabpZBfc" : {
"name" : "Comp1 Ltd",
"users" : {
"-JiGh_31GA20JabpZBfe" : true,
"-JiGh_31GA20JabpZBff" : true,
"-JiGh_31GA20JabpZBea" : true
},
"employees" : {
"-JiGh_31GA20JabpZBeb" : true,
"-JiGh_31GA20JabpZBec" : true
}
},
"-JiGh_31GA20JabpZBfd" : {
"name" : "company2 PLC",
"users" :{
"WgnHjk5D8xbuYeA7VDM3ngKwCYV2" : true
},
"employees" :{
"-JiGh_31GA20JabpZBce" : true
}
}
},
"users" : {
"8UnM6LIiZJYAHVdty6gzdD8oVI42": {
"firstName" : "Peter",
"lastName" : "Piper",
"email" : "peter.piper@testtest.com",
"organization" : ""
},
"-JiGh_31GA20JabpZBfe" : {
"firstName" : "Joe",
"lastName" : "Blogs",
"email" : "joe.blogs@co1.com",
"organization" : "-JiGh_31GA20JabpZBfc"
},
"-JiGh_31GA20JabpZBff" : {
"firstName" : "Sally",
"lastName" : "McSwashle",
"email" : "sally.mcswashle@co1.com",
"organization" : "-JiGh_31GA20JabpZBfc"
},
"-JiGh_31GA20JabpZBea" : {
"firstName" : "Eva",
"lastName" : "Rushtock",
"email" : "eva.rushtock@payrollings.com",
"organization" : "-JiGh_31GA20JabpZBfc"
},
"WgnHjk5D8xbuYeA7VDM3ngKwCYV2" : {
"firstName" : "test",
"lastName" : "user",
"email" : "test.user@google.com",
"organization" : "-JiGh_31GA20JabpZBfd"
}
},
"employees" : {
"-JiGh_31GA20JabpZBeb" : {
"organization" : "-JiGh_31GA20JabpZBfc",
"firstName" : "Johnny",
"lastName" : "Baggs",
"email" : "j.baggss@financeco.com",
"employeeNumber" : "ASV123456"
},
"-JiGh_31GA20JabpZBec" : {
"organization" : "-JiGh_31GA20JabpZBfc",
"firstName" : "Maheswari",
"lastName" : "Sanjal",
"email" : "mahe.sanjal@financeco.com",
"employeeNumber" : "ASV111111"
},
"-JiGh_31GA20JabpZBce" : {
"organization" : "-JiGh_31GA20JabpZBfd",
"firstName" : "Fedde",
"lastName" : "le Grande",
"email" : "fedde.grande@payrollings.com",
"employeeNumber" : "ASV111111"
}
}
}
尝试 #2 规则:https://gist.github.com/peteski22/e1be434cd1ea8ec2e630bec6d8aa714f
{
"rules" : {
"admins" : {
".read" : "root.child('admins').hasChild(auth.uid)",
".write" : "root.child('admins').hasChild(auth.uid)"
},
"users" : {
".indexOn": [ "organization" ],
"$user" : {
".read" : "data.child('organization').val() === root.child('users').child(auth.uid).child('organization').val()",
".write" : "root.child('admins').hasChild(auth.uid)"
}
},
"organizations" : {
".indexOn": [ "users", "employees" ],
"$organization" : {
".read" : "$organization === root.child('users').child(auth.uid).child('organization').val()",
".write" : "root.child('admins').hasChild(auth.uid)"
}
},
"employees" : {
".indexOn": [ "organization" ],
"$employee" : {
".read" : "data.child('organization').val() === root.child('users').child(auth.uid).child('organization').val()",
".write" : "data.child('organization').val() === root.child('users').child(auth.uid).child('organization').val()"
}
}
}
}
现在我可以在每个集合中很好地锁定数据,但获取任何信息的唯一方法是知道组织 ID,获取该组织,然后通过他们的 ID 获取每个员工.虽然上面用于结构化数据的文档(部分:加入扁平数据)似乎表明这样做很好,但来自 OO 和 SQL 背景感觉很奇怪..这通常意味着..“我做错了” .
如果有人对我是否走在正确的轨道上或尝试什么有任何建议,将不胜感激。
谢谢 彼得
【问题讨论】:
标签: firebase firebase-realtime-database multi-tenant firebase-security nosql