Js中如何按对象过滤对象

Question

我的第一个对象是：

 {Color: [
         {display: "RED", value: "5433", count: "12"}
         {display: "Black", value: "5446", count: "37"}    
        ]
        Brand: [
         {display: "NIKAVI", value: "5458", count: "58", brand: }
         {display: "BOSCH", value: "5570", count: "7",}
         {display: "REPLAY", value: "5497", count: "132",}
        ]
        Category: [
         {display: "Motorbike Horns", value: "1320", count: "8"}
         {display: "LED Lamps", value: "1325", count: "3"}
        ]
    }

我的第二个对象是：

{Brand: "5458", Color: "5446",Category:[1320,75]}

我必须使用第二个对象值过滤第一个对象值。我尝试了很多，但找不到好主意。我在 reactJs 工作。

Answer 1

你可以试试这个；

firstObj = {Color: [
  {display: "RED", value: "5433", count: "12"},
  {display: "Black", value: "5446", count: "37"}    
 ],
 Brand: [
  {display: "NIKAVI", value: "5458", count: "58",},
  {display: "BOSCH", value: "5570", count: "7",},
  {display: "REPLAY", value: "5497", count: "132",}
 ]
};

secondObj={Brand: "5458", Color: "5446"}

// solution:
const result =Object.keys(secondObj).map(sk => firstObj[sk].filter(fo => fo.value === secondObj[sk]))
    
    
    console.log(result)

Answer 2

您可以简单地在第二个对象上迭代键值对，然后使用Array#find 方法（如果您需要一个数组或有多个数组，则使用Array#filter 方法）来获得结果。

const obj1 = {Color: [
         {display: "RED", value: "5433", count: "12"},
         {display: "Black", value: "5446", count: "37"}    
        ],
        Brand: [
         {display: "NIKAVI", value: "5458", count: "58", brand: ''},
         {display: "BOSCH", value: "5570", count: "7",},
         {display: "REPLAY", value: "5497", count: "132",}
        ],
        Category: [
         {display: "Motorbike Horns", value: "1320", count: "8"},
         {display: "LED Lamps", value: "1325", count: "3"}
        ]
    };

;
const obj2={Brand: "5458", Color: "5446",Category:[1320,75]};



const res = {};

for (let [key, value] of Object.entries(obj2)) {
  res[key] = obj1[key].filter(o => Array.isArray(value) ? value.some(v => v == o.value) : o.value === value) 
}


console.log(res);