无法在报表生成器中选择多个值

Question

我在下面的报告构建器中犯了一个逻辑错误，有 2 个连接到@Income 参数的 Sequel 查询，但是在报告中我得到了这个结果，这没有意义，因为它只显示相同的收入。

我认为这是因为我无法选择多种收入。当我尝试选择多个值时出现此错误。

这个查询可以执行，但效率不高。我也遇到了同样的年龄查询，我无法选择多个年龄，如您在错误图片中看到的那样。

(SELECT MIN(YearlyIncome) FROM vTargetCustomer WHERE (@Age = Age) AND (@Income = YearlyIncome) AND (@Buyer = BikeBuyer)) as MinIncome,
(SELECT MAX(YearlyIncome) FROM vTargetCustomer WHERE (@Age = Age) AND (@Income = YearlyIncome) AND (@Buyer = BikeBuyer)) as MaxIncome

这是我的存储过程 (DataSet1)

CREATE PROC GET_TargetCustomer (
@Age INT,
@Income int,
@Buyer int



) as

BEGIN
SELECT DISTINCT


   (SELECT AVG(Age) FROM vTargetCustomer WHERE (@Age = Age) AND (@Income = YearlyIncome) AND (@Buyer = BikeBuyer)) AS AVGAge,
(SELECT SUM(BikeBuyer) FROM vTargetCustomer WHERE (@Age = Age) AND (@Income = YearlyIncome) AND (@Buyer = BikeBuyer)) as TotalBuyers,
(SELECT MAX(Age)  FROM vTargetCustomer WHERE (@Age = Age) AND (@Income = YearlyIncome) AND (@Buyer = BikeBuyer)) AS OldestCustomer,
(SELECT AVG(YearlyIncome) FROM vTargetCustomer WHERE(@Age = Age) AND (@Income = YearlyIncome) AND (@Buyer = BikeBuyer)) as AVGIncome,
(SELECT MIN(Age)  FROM vTargetCustomer WHERE (@Age = Age) AND (@Income = YearlyIncome) AND (@Buyer = BikeBuyer)) AS YoungestCustomer,
(SELECT MIN(YearlyIncome) FROM vTargetCustomer WHERE (@Age = Age) AND (@Income = YearlyIncome) AND (@Buyer = BikeBuyer)) as MinIncome,
(SELECT MAX(YearlyIncome) FROM vTargetCustomer WHERE (@Age = Age) AND (@Income = YearlyIncome) AND (@Buyer = BikeBuyer)) as MaxIncome


END

GO

我已经为每个参数创建了数据集

年龄参数的AgeDataSet

SELECT DISTINCT Age FROM vTargetCustomer ORDER BY Age ASC

IncomeDS 收入参数

SELECT DISTINCT YearlyIncome FROM vTargetCustomer ORDER BY YearlyIncome ASC

买方参数的BuyerDS

SELECT DISTINCT BikeBuyer FROM vTargetCustomer ORDER BY BikeBuyer ASC

谁能帮我解决这个问题？

Answer 1

如果您在参数中使用多个值，则查询需要能够使用 IN 而不是等号 (=) 来使用它们。

您没有将它们全部组合在一个 SELECT 中是有原因的吗？

SELECT AVG(Age) AVGAge, SUM(BikeBuyer) TotalBuyers, MAX(Age), MIN(Age)
FROM vTargetCustomer 
WHERE (Age = @Age) 
    AND (Income IN (@YearlyIncome)) 
    AND (BikeBuyer = @Buyer)