【问题标题】:Error Decode: TypeError: Cannot read property '2' of undefined错误解码:TypeError:无法读取未定义的属性“2”
【发布时间】:2021-11-29 14:09:02
【问题描述】:

我一直在努力理解以下脚本的错误之处。该脚本的目的是每当“individual_client_sheet”中的唯一 ID 与两个工作表中的行中的一个 ID 匹配时删除一行:“clients_database”和“clients_sheet”。到目前为止,代码能够删除每张工作表中的相应行,但错误消息“TypeError:无法读取未定义的属性'2'”不断出现,我无法理解为什么。其次,该脚本不会重置“individual_client_sheet”中的字段,因此在删除记录后它似乎停止工作。这是脚本:

   function deleteClientRecord () {
   // Get Active Sheets
    var ss = SpreadsheetApp.getActiveSpreadsheet();
    var shClient = ss.getSheetByName ('individual_client_sheet');
    var shData = ss.getSheetByName ('clients_database');
    var shClientsList = ss.getSheetByName ('clients_sheet');

   // Obtain and verify user response 
    var ui = SpreadsheetApp.getUi();
    var response = ui.alert ('Delete', 'Are you sure you want to remove this record?', ui.ButtonSet.YES_NO);

   if (response == ui.Button.NO) {
    return;
   }

   var searchValue = shClient.getRange('AF2').getValue();
   var shDataValues = shData.getDataRange().getValues();
   var shClientsListValues = shClientsList.getDataRange().getValues();


   // Delete record from 'clients_database'
      var shDataValuesFound = false; 

      for (var i = 0; i < shDataValues.length; i++) {
      var rowValue = shDataValues[i]; 

       if (rowValue[3] == searchValue) {
        var iRow = i+1;
        shData.deleteRow(iRow);
       }
      }


  // Delete record from All CLients Sheet 
     var shClientsListValuesFound = false; 

     for (var j = 0; i < shClientsListValues.length; j++) {
     var rowValue2 = shClientsListValues[j];

     if (rowValue2[2] == searchValue) {
      var jRow = j+1;
      shClientsList.deleteRow(jRow);

 ui.alert('Record deleted for - Client #' + shClient.getRange('AF2').getValue() + '');  
  }
 }

 // Delete Fields

 // Checkboxes 
   shClient.getRange('Z10:AA13').setValue(false);
   shClient.getRange('AP5:AQ5').setValue(false);
  
  // Basic Client Info
    shClient.getRange('B5:G5').clearContent(); // Business Name
    shClient.getRange('AF2').clearContent(); // Client ID
    shClient.getRange('B10').clearContent(); // website
    shClient.getRange('B12:B13').clearContent(); // billing add         
    shClient.getRange('B15:B16').clearContent(); // postal add 
    shClient.getRange('B18').clearContent(); // primary contact 
    shClient.getRange('B20').clearContent(); // phone
    shClient.getRange('B22').clearContent(); // email
    shClient.getRange('B26').clearContent(); // additional info 1          
    shClient.getRange('B28').clearContent(); // additional info 2 

  // Client Status 
    shClient.getRange('AN5:AO5').clearContent(); // client status
    shClient.getRange('AP5:AQ5').clearContent().setValue(false); // importance


  shClientsListValuesFound = true;
  shDataValuesFound = true;
 return;
}

【问题讨论】:

    标签: google-apps-script google-sheets runtime-error delete-row


    【解决方案1】:

    我认为是错误行:

     for (var j = 0; i < shClientsListValues.length; j++) {
    

    应该是j 而不是i

     for (var j = 0; j < shClientsListValues.length; j++) {
    

    【讨论】:

    • lmao,是的,我刚刚意识到拼写错误:') 谢谢
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