显然OpenURL 在 iOS 10 中已被弃用。是否有人有任何文档说明原因或可以解释下一步该做什么？我已经查看了 Apple 网站，发现了一些与 OpenURL 相关的内容，这就是他们说现在要使用的内容：
UIApplication.shared().open(url: URL, options: [String: AnyObject], completionHandler: ((Bool) -> Void)?)
是否有任何证据表明这是在 Swift 3.0 中使用 OpenURL 的新方法？另外options:和completionHandler:参数分别使用什么值？
【问题讨论】：
Swift 3+：
func open(scheme: String) {
if let url = URL(string: scheme) {
if #available(iOS 10, *) {
UIApplication.shared.open(url, options: [:],
completionHandler: {
(success) in
print("Open \(scheme): \(success)")
})
} else {
let success = UIApplication.shared.openURL(url)
print("Open \(scheme): \(success)")
}
}
}
用法：
open(scheme: "tweetbot://timeline")
【讨论】：
快速修复：
// Objective-C
UIApplication *application = [UIApplication sharedApplication];
[application openURL:URL options:@{} completionHandler:nil];
// Swift
UIApplication.shared.open(url, options: [:], completionHandler: nil)
完整答案：
http://useyourloaf.com/blog/openurl-deprecated-in-ios10/
致谢：Keith Harrison (useyourloaf.com)
【讨论】：
empty 选项字典将产生与 openUrl 相同的行为。
否则：
+-------------------------------------------------+----------------------------------------------------------------------------------------------------------------------------------------------+
| UIApplicationOpenURLOptionsSourceApplicationKey | NSString containing the bundle ID of the originating application |
+-------------------------------------------------+----------------------------------------------------------------------------------------------------------------------------------------------+
| UIApplicationOpenURLOptionsAnnotationKey | property-list typed object corresponding to what the originating application passed in UIDocumentInteractionController's annotation property |
+-------------------------------------------------+----------------------------------------------------------------------------------------------------------------------------------------------+
| UIApplicationOpenURLOptionsOpenInPlaceKey | bool NSNumber, set to YES if the file needs to be copied before use |
+-------------------------------------------------+----------------------------------------------------------------------------------------------------------------------------------------------+
来自 UIApplication.h
// Options are specified in the section below for openURL options. An empty options dictionary will result in the same
// behavior as the older openURL call, aside from the fact that this is asynchronous and calls the completion handler rather
// than returning a result.
// The completion handler is called on the main queue.
- (void)openURL:(NSURL*)url options:(NSDictionary<NSString *, id> *)options completionHandler:(void (^ __nullable)(BOOL success))completion NS_AVAILABLE_IOS(10_0) NS_EXTENSION_UNAVAILABLE_IOS("");
UIKIT_EXTERN UIApplicationOpenURLOptionsKey const UIApplicationOpenURLOptionsSourceApplicationKey NS_SWIFT_NAME(sourceApplication) NS_AVAILABLE_IOS(9_0); // value is an NSString containing the bundle ID of the originating application
UIKIT_EXTERN UIApplicationOpenURLOptionsKey const UIApplicationOpenURLOptionsAnnotationKey NS_SWIFT_NAME(annotation) NS_AVAILABLE_IOS(9_0); // value is a property-list typed object corresponding to what the originating application passed in UIDocumentInteractionController's annotation property
UIKIT_EXTERN UIApplicationOpenURLOptionsKey const UIApplicationOpenURLOptionsOpenInPlaceKey NS_SWIFT_NAME(openInPlace) NS_AVAILABLE_IOS(9_0); // value is a bool NSNumber, set to YES if the file needs to be copied before use
【讨论】：
新增UIApplication方法openURL:options:completionHandler:，异步执行，调用主队列上指定的completion handler（该方法替代openURL:）。
这在 Additional Framework Changes > UIKit 下：https://developer.apple.com/library/prerelease/content/releasenotes/General/WhatsNewIniOS/Articles/iOS10.html
【讨论】：
openURL:options:completionHandler: 是我们应该使用的新功能，还是我在问题中建议的功能？你仍然使用UIApplication.shared()...
openURL:options:completionHandler: 函数是openUrl 的替代品。并非所有文档都已更新，some 仍指向已弃用的代码。
在加载 url 之前，您需要先进行一些检查。请检查以下代码。
if ([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:@"https://www.gmail.com"]]){
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"https://www.gmail.com"] options:@{} completionHandler:^(BOOL success) {
//completion codes here
}];
}
我希望这会有所帮助。
【讨论】：
如果您的应用仍支持iOS 9 或更低版本，请继续使用旧的openURL。如果您的部署目标是iOS 10，您应该只迁移到新的。
【讨论】：
让实际：
[String: AnyObject] = ["xxx key": "xxx value" as AnyObject, "yyy key": "yyy value" as AnyObject]
UIApplication.shared.open(URL(string: "http:google.com")!, options: actual, completionHandler: {(true) -> Swift.Void in
print("Refresh")
})
其中 xxx 和 yyy 是您要打印的任何字符串或将它们留空。
【讨论】：
您可以使用函数打开设置：
func showAlert(title:String, message:String){
let alert = UIAlertController(title: title,
message: message,
preferredStyle: UIAlertController.Style.alert)
let okAction = UIAlertAction(title: "OK", style: .cancel, handler: nil)
alert.addAction(okAction)
let settingsAction = UIAlertAction(title: "Settings", style: .default, handler: { _ in
// Take the user to Settings app to possibly change permission.
guard let settingsUrl = URL(string: UIApplication.openSettingsURLString) else { return }
if UIApplication.shared.canOpenURL(settingsUrl) {
if #available(iOS 10.0, *) {
UIApplication.shared.open(settingsUrl, completionHandler: { (success) in
// Finished opening URL
})
} else {
// Fallback on earlier versions
UIApplication.shared.openURL(settingsUrl)
}
}
})
alert.addAction(settingsAction)
present(alert, animated: true, completion: nil)
}
像下面这样调用这个函数
showAlert(title: "Unable to access the Photos", message: "To enable access, go to Settings > Privacy > Photos and turn on Photos access for this app.")
【讨论】：