如何使用 Lodash 按类别和日期过滤和排序数组

Question

大家好，我是新手，我尝试使用 lodash 对对象数组进行排序和过滤，我不知道是正确的解决方案，但我知道可行，我有一些这样的数组...

contactList =[    { 
      "ChatCount": 2, "chatid": 10000413, "createdon": "2018-10-25T13:49:50.9900000", "isArchive": 0, "isOnline": false ,
      "members":[{"id": "60259166", "lastseen": 15261867,"name": "la", "picture": "/la/5285871.250.jpg"}],
      "message": "",
      "message_cnt": 1,
      "messageid": 1,
      "newest_message": "2018-10-25T13:49:50.9900000",
      "oldest_message": "2018-10-25T13:49:50.9900000",
      "received_cnt": 0,
      "sentby": [{"id":59,"name":"betsynray","picture":"/betsynray/2884P1010025250.jpg","lastseen":1164}],
      "unread_cnt": 1
     },
     {
         "ChatCount": 2, "chatid": 61247987, "createdon": "2018-10-25T13:49:14.9170000", "isArchive": 0,"isOnline": true,
         "members":[{"id": 61247987, "lastseen": 15318187,"name": "li", "picture": "/li/4705502.250.jpg"}],
         "message": "good",
        "message_cnt": 2,
        "messageid": 2,
        "newest_message": "2018-10-31T10:20:29.5000000",
        "oldest_message": "2018-10-25T13:47:59.6700000",
        "received_cnt": 0,
        "sentby": [{"id":59,"name":"mm","picture":"/mm/2884P1010025250.jpg","lastseen":1164}],
        "unread_cnt": 3
     }

]

他们我想过滤 (sentBy.lastseen > 18000) 并使用 (newest_message) 按最近日期排序>

contactList.sort(function (o) { return moment(o.NEWEST_MESSAGE).format('YYYYMMDD')}).reverse();

这个工作，但现在我也尝试使用 lastseen 过滤，我尝试使用 lodas 和 momentjs 进行类似的操作

 function any() {

   var status = _(contactList)
        .filter(function (a) { return a.MEMBERS[0].lastseen > 1800000 }) 
        .sort(function (o) { return moment(o.NEWEST_MESSAGE).format('YYYYMMDD')}).reverse() // sort names
        .value();
        return status;

}

latseen 过滤器运行良好，但没有按最近日期排序，我做错了什么有人可以帮助我吗？提前非常感谢你

Answer 1

由于您的日期是 ISO 格式，因此您实际上不需要任何东西，只需要 orderBy 和 desc，如下所示：

var data = [{ "ChatCount": 2, "chatid": 10000413, "createdon": "2018-10-25T13:49:50.9900000", "isArchive": 0, "isOnline": false, "members": [{ "id": "60259166", "lastseen": 15261867, "name": "la", "picture": "/la/5285871.250.jpg" }], "message": "", "message_cnt": 1, "messageid": 1, "newest_message": "2018-10-25T13:49:50.9900000", "oldest_message": "2018-10-25T13:49:50.9900000", "received_cnt": 0, "sentby": [{ "id": 59, "name": "betsynray", "picture": "/betsynray/2884P1010025250.jpg", "lastseen": 1164 }], "unread_cnt": 1 }, { "ChatCount": 2, "chatid": 61247987, "createdon": "2018-10-25T13:49:14.9170000", "isArchive": 0, "isOnline": true, "members": [{ "id": 61247987, "lastseen": 15318187, "name": "li", "picture": "/li/4705502.250.jpg" }], "message": "good", "message_cnt": 2, "messageid": 2, "newest_message": "2018-10-31T10:20:29.5000000", "oldest_message": "2018-10-25T13:47:59.6700000", "received_cnt": 0, "sentby": [{ "id": 59, "name": "mm", "picture": "/mm/2884P1010025250.jpg", "lastseen": 1164 }], "unread_cnt": 3 } ];

var result = _(data)
  .filter(x => _.get(x, 'members.0.lastseen') > 1800000)
  .orderBy('newest_message', 'desc')
  .value();

console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>

Answer 2

您需要的是使用简单的Date 对象排序，moment 根本不需要（但是您仍然可以用于复杂的日期逻辑。

应该只是：

_.orderBy(contactList, o=>new Date(o.newest_message), 'desc')

这是一个工作示例：

var contactList =[    { 
      "ChatCount": 2, "chatid": 10000413, "createdon": "2018-10-25T13:49:50.9900000", "isArchive": 0, "isOnline": false ,
      "members":[{"id": "60259166", "lastseen": 15261867,"name": "la", "picture": "/la/5285871.250.jpg"}],
      "message": "",
      "message_cnt": 1,
      "messageid": 1,
      "newest_message": "2018-10-25T13:49:50.9900000",
      "oldest_message": "2018-10-25T13:49:50.9900000",
      "received_cnt": 0,
      "sentby": [{"id":59,"name":"betsynray","picture":"/betsynray/2884P1010025250.jpg","lastseen":1164}],
      "unread_cnt": 1
     },
     {
         "ChatCount": 2, "chatid": 61247987, "createdon": "2018-10-25T13:49:14.9170000", "isArchive": 0,"isOnline": true,
         "members":[{"id": 61247987, "lastseen": 15318187,"name": "li", "picture": "/li/4705502.250.jpg"}],
         "message": "good",
        "message_cnt": 2,
        "messageid": 2,
        "newest_message": "2018-10-31T10:20:29.5000000",
        "oldest_message": "2018-10-25T13:47:59.6700000",
        "received_cnt": 0,
        "sentby": [{"id":59,"name":"mm","picture":"/mm/2884P1010025250.jpg","lastseen":1164}],
        "unread_cnt": 3
     }

];

var st = _(contactList)
        .filter(a => a.members[0].lastseen > 1800000) 
        .orderBy(o=>new Date(o.newest_message), 'desc')
        .value();
        
console.log(st);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>

您可以使用asc 进行升序排序，使用desc 进行降序排序（最后一个参数）。您还可以传递按名称排序所需的任何其他字段（如果是简单值），或者您可以传递一个回调，返回基于它将排序的值。

Answer 3

您可以尝试将其格式化为时间戳吗：

.sort(function (o) { return moment(o.newest_message).unix()})

如果我没看错，您不需要将 contactList 包装在 lodash 函数中...

filter、sort 和 reverse 是本机数组函数。

---

var status = contactList
        .filter(function (a) { return a.members[0].lastseen > 1800000 })
        .sort(function (o) { return moment(o.newest_message).unix() })
        .reverse();
return status;