【发布时间】:2022-01-22 03:31:50
【问题描述】:
这与lodash unique based on attribute 的要求相反,这里我想通过忽略一个(或多个)属性来使数组唯一。
所以在下面,我不关心“年龄”属性(可能有多个记录,我只想保留细节变化的地方)。
const arr = [{
"id": 1,
"name": "Jen",
"age": 31,
"eyecolor": "blue",
"hair": "brown",
}, {
"id": 1,
"name": "Jen",
"age": 32,
"eyecolor": "blue",
"hair": "brown"
}, {
"id": 2,
"name": "Jules",
"age": 31,
"eyecolor": "blue",
"hair": "brown"
}, {
"id": 2 "name": "Brian",
"age": 40,
"eyecolor": "blue",
"hair": "brown"
}];
const unique = _.uniqBy(arr, 'id');
console.log(unique);
// const uniqueNot = _.uniqExcept(arr, 'age');
// keeps one of the Jen objects, but both of the Jules/Brian objects
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.js"></script>
正如评论所说,我希望以上内容保留 Jen 对象之一,但同时保留 Jules/Brian 对象。
我想我可以这样做:
const arr = [{
"id": 1,
"name": "Jen",
"age": 31,
"eyecolor": "blue",
"hair": "brown",
}, {
"id": 1,
"name": "Jen",
"age": 32,
"eyecolor": "blue",
"hair": "brown"
}, {
"id": 2,
"name": "Jules",
"age": 31,
"eyecolor": "blue",
"hair": "brown"
}, {
"id": 2,
"name": "Brian",
"age": 40,
"eyecolor": "blue",
"hair": "brown"
}];
const omissionComparator = (withoutKeys) => (a, b) => _.isEqual(_.omit(a, withoutKeys), _.omit(b, withoutKeys))
const uniqueWithoutAge = _.uniqWith(_.orderBy(arr, ['id','age'], ['asc', 'desc']), omissionComparator('age'));
console.log(uniqueWithoutAge);
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.js"></script>
但是有没有办法在没有自定义比较器和/或必须先对数组进行排序的情况下做到这一点?
【问题讨论】:
-
我不清楚您为什么将排序作为此操作的一部分。结果是一样的,afaic。
orderBy似乎没有必要。 -
@kaliatech 保留了年龄为 31 的未排序 Jen,保留了年龄为 32 的排序 Jen。此外,按 ID 排序会保留原始顺序(但不一定总是如此)
标签: javascript lodash unique