【发布时间】:2019-03-18 11:45:49
【问题描述】:
我正在尝试测试从 React Native Button 元素调用组件方法。
由于某种原因,除非我同时做这两件事,否则测试会失败。
wrapper.find(Button).first().props().onPress();
wrapper.find(Button).first().simulate('press');
如果我注释掉其中任何一行,测试就会失败,表明 expect(instance.toggleEmailPasswordModal).toHaveBeenCalled(); 失败。
这是我的组件:
import React, { Component } from 'react';
import { Button, SafeAreaView, Text } from 'react-native';
import EmailPasswordModal from './EmailPasswordModal/EmailPasswordModal';
class Login extends Component {
state = {
emailPasswordModalVisible: false,
};
toggleEmailPasswordModal = () => {
console.log('TOGGLED!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!');
const { emailPasswordModalVisible } = this.state;
this.setState({ emailPasswordModalVisible: !emailPasswordModalVisible });
};
render() {
const { emailPasswordModalVisible } = this.state;
return (
<SafeAreaView>
<EmailPasswordModal
visible={ emailPasswordModalVisible }
close={ this.toggleEmailPasswordModal }
/>
<Text>Login Screen!</Text>
<Button
onPress={ this.toggleEmailPasswordModal }
title="Login with Email and Password"
color="#841584"
accessibilityLabel="Login with Email and Password"
/>
</SafeAreaView>
);
}
}
export default Login;
这是我的测试:
import React from 'react';
import ShallowRenderer from 'react-test-renderer/shallow';
import { shallow } from 'enzyme';
import { Button } from 'react-native';
import Login from './Login';
describe('Login Screen', () => {
describe('Snapshot Tests', () => {
it('renders the screen with default state', () => {
const renderer = new ShallowRenderer();
const props = {};
renderer.render(<Login { ...props } />);
expect(renderer.getRenderOutput()).toMatchSnapshot();
});
});
describe('Functional Tests', () => {
it('calls the toggleEmailPasswordModal method', () => {
const wrapper = shallow(<Login />);
const instance = wrapper.instance();
jest.spyOn(instance, 'toggleEmailPasswordModal');
wrapper.find(Button).first().props().onPress();
wrapper.find(Button).first().simulate('press');
expect(instance.toggleEmailPasswordModal).toHaveBeenCalled();
});
});
});
奇怪的是,当测试运行时,输出显示“TOGGLED!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! !!!!!!!!!!!!!!!”两次因为组件中的日志记录。
但是,如果我将 expect 更改为:
expect(instance.toggleEmailPasswordModal).toHaveBeenCalledTimes(1);
测试通过。
如果我将expect 更改为:
expect(instance.toggleEmailPasswordModal).toHaveBeenCalledTimes(2);
测试失败,说 toggleEmailPasswordModal 只被调用了 1 次。
为什么我需要这两条wrapper.find(Button)... 行?我从未见过任何其他测试都需要它们。
谢谢, 贾斯汀
更新:
我更新了我的测试如下:
it('calls the toggleEmailPasswordModal method', () => {
const wrapper = shallow(<Login />);
const instance = wrapper.instance();
jest.spyOn(instance, 'toggleEmailPasswordModal');
wrapper.find(Button).first().props().onPress();
wrapper.find(Button).first().simulate('press');
expect(instance.toggleEmailPasswordModal).toHaveBeenCalled();
// I ADDED THIS SECTION HERE
expect(instance.state.emailPasswordModalVisible).toBe(true);
});
测试失败,因为instance.state.emailPasswordModalVisible = false。这很奇怪,因为显然调用了 toggleEmailPasswordModal。但是,由于我怀疑它实际上被调用了两次,所以我将测试更新如下:
it('calls the toggleEmailPasswordModal method', () => {
const wrapper = shallow(<Login />);
const instance = wrapper.instance();
jest.spyOn(instance, 'toggleEmailPasswordModal');
wrapper.find(Button).first().props().onPress();
// CHANGES START HERE
// wrapper.find(Button).first().simulate('press');
// expect(instance.toggleEmailPasswordModal).toHaveBeenCalled();
expect(instance.state.emailPasswordModalVisible).toBe(true);
});
你猜怎么着?测试正常通过。所以很明显,两次调用wrapper.find... 函数实际上就是两次调用toggleEmailPasswordModal 方法。那么,如果我不调用两次,为什么它无法检测到它?为什么它错误地认为该方法只被调用过一次?
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标签: react-native jestjs