【发布时间】:2018-07-11 05:53:56
【问题描述】:
我需要返回一个包含正则表达式并插入实例变量的字符串。字符串需要如下所示:
"SELECT field1, field2 CASE WHEN REGEXP_CONTAINS(field3, r"^\".*\"$") THEN 'this' WHEN REGEXP_CONTAINS(field3, r"^\[.*]$") THEN 'that' WHEN field3 = '(not provided)' THEN NULL ELSE 'the_other' END AS better_field_3, field4 FROM `interpolated_table_name1` AS tbl LEFT JOIN `interpolated_table_name2` AS tbl2 ON blah = blah"
我用这段代码来生成它:
def string_query
statement =
<<-HEREDOC
SELECT
field1,
field2
CASE WHEN REGEXP_CONTAINS(field3, r"^\".*\"$") THEN 'this'
WHEN REGEXP_CONTAINS(field3, r"^\[.*]$") THEN 'that'
WHEN field3 = '(not provided)' THEN NULL
ELSE 'the_other' END AS better_field_3,
field4
FROM `#{@dynamic_table_name1}` AS tbl
LEFT JOIN `#{@dynamic_table_name2}` AS tbl2
ON blah = blah
HEREDOC
statement.squish!
end
字符串用双引号括起来,这就是正则表达式被转义的原因。当我在数据库上运行此 SQL 以执行查询时,正则表达式已被更改,并且未删除要转义的额外反斜杠。
【问题讨论】:
标签: ruby regex string heredoc string-interpolation