【发布时间】:2017-10-14 22:13:01
【问题描述】:
我正在尝试从触发器运行存储过程,以确保订单按照插入数据库的顺序打印。如果我手动运行存储过程,它会在 20 秒内完成。如果我从触发器运行它,它永远不会完成。
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
SET ARITHABORT OFF
GO
CREATE PROCEDURE [dbo].[usr_despatch_m2] @order VARCHAR(10)
AS
SET XACT_ABORT ON
SET NOCOUNT ON
--DROP TABLE #bundle (bundle int)
DECLARE @sql VARCHAR(1000), @result INT, @text varchar(1000)
SET @sql = 'D:\csserver\bin\runvtorddesp_m.bat '+@order
-- set @sql = 'command.com /c sdespatch '+ @order
EXEC @result = master..xp_cmdshell @sql, no_output
IF @result in (0,1010)
BEGIN
EXEC manufg.dbo.op_populate_shipping_data_dev @order
IF @order LIKE '[T,Y,R,S]%'
BEGIN
EXEC [SERVER2].sp_manufg.[dbo].[pod_print_can_inv] @order
END
SET @sql = 'command.com /c PRINT /D:\\SERVER1\MEM-SHIPPING-INVOICE \\SERVER1\e$\PODPDF\'+rtrim(@order)+'.PDF'
EXEC @result = master..xp_cmdshell @sql, NO_OUTPUT
END
BEGIN
SET @text = (SELECT
CASE @result
WHEN 0 THEN 'Order despatched successfully'
WHEN 1010 THEN 'Order despatched successfully'
WHEN 1 THEN 'Order error not found in order header'
WHEN 2 THEN 'Order at incorrect status'
WHEN 3 THEN 'Order despatch held'
WHEN 4 THEN 'Order is not web order'
WHEN 5 THEN 'Order not fully processed by DataLinx'
WHEN 6 THEN 'Order is in error'
WHEN 7 THEN 'Order is in error'
WHEN 8 THEN 'Order header is locked'
WHEN 9 THEN 'Stock item is locked'
WHEN 13 THEN 'Order number not found'
WHEN 33 THEN 'Unable to lock stock allocations (stallocm)'
WHEN 34 THEN 'Unable to lock stock batch file (stquem)'
WHEN 40 THEN 'Unable to update EIPOLASTDT system key'
WHEN 50 THEN 'Unable to unlock EDI order'
ELSE 'Order in error'
END )
SET @text = rtrim(@order) +' ' + @text
SET @sql = 'echo ' + @text + ' > E:\DespatchErrors\Manufg\'+rtrim(@order)+'.txt'
EXEC @result = master..xp_cmdshell @sql, no_output
SET @sql = 'command.com /c PRINT /D:\\SERVER1\MEM-SHIPPING-INVOICE \\SERVER1\e$\DespatchErrors\MANUFG\'+rtrim(@order)+'.txt'
EXEC @result = master..xp_cmdshell @sql, NO_OUTPUT
END
触发器很简单
ALTER TRIGGER [dbo].[usr_order_despatch_m_c] on [dbo].[pod_mfg_inv]
instead of insert
as
SET XACT_ABORT ON
SET NOCOUNT ON
DECLARE @order varchar(10)
SET @order = (select order_no from inserted)
EXEC usr_despatch_m2 'T568138'
似乎陷入困境的存储过程是
GO
SET QUOTED_IDENTIFIER ON
SET XACT_ABORT ON
SET ARITHABORT ON
GO
ALTER PROCEDURE [dbo].[pod_print_can_inv]
@myOrder CHAR(10)
AS
DECLARE
@mySql VARCHAR(1000),
@result INT
BEGIN
--Select the right report since Trade invoices are different to Retail dispatch notes
IF @myOrder LIKE 'R%'
BEGIN
SET @mySql = 'dtsrun /S SERVER2 /E /N PODCanRetailInvPDF /A "myFilter":"8"="(lfdinv = ""' + RTRIM(@myOrder) + '"")"'
END
-- Canadian Battle For Vedros Invoices
IF @myOrder LIKE 'Y%'
BEGIN
SET @mySql = 'dtsrun /S SERVER2 /E /N PODVedrosInvoiceWithTerms /A "myFilter":"8"="(lfdinv = ""' + RTRIM(@myOrder) + '"")"'
END
-- Canadian Trade Invoices
ELSE
BEGIN
SET @mySql = 'dtsrun /S SERVER2 /E /N PODCanTradeInvWithTerms /A "myFilter":"8"="(lfdinv = ""' + RTRIM(@myOrder) + '"")"'
END
EXEC @result = master..xp_cmdshell @mySql, NO_OUTPUT
IF @result = 0 BEGIN
WAITFOR DELAY '00:00:01'
SET @mySql = 'DEL \\SERVER1\E$\PODPDF\TST\' + RTRIM(@myOrder) + '.pdf'
EXEC @result = master..xp_cmdshell @mySql, NO_OUTPUT
WAITFOR DELAY '00:00:01'
SET @mySql = 'REN \\SERVER1\E$\PODPDF\TST\PDFCreatorDocument.pdf ' + RTRIM(@myOrder) + '.pdf'
EXEC @result = master..xp_cmdshell @mySql, NO_OUTPUT
WAITFOR DELAY '00:00:01'
-- Stop MSAccess on the server
SET @mySql = 'PSKILL msaccess.exe'
EXEC master..xp_cmdshell @mySql, NO_OUTPUT
WAITFOR DELAY '00:00:10'
/*
IF @myOrder LIKE 'Y%'
BEGIN
SET @mySql = 'COMMAND AcroRd32.exe /t "\\SERVER1\E$\PODPDF\TST\' + RTRIM(@myOrder) + '.pdf" "\\SERVER1\BACKOFFICE" "Canon iR-ADV C5235/5240 PCL5c" "IP_172.16.235.100"'
EXEC master..xp_cmdshell @mySql, NO_OUTPUT
END*/
SET @mySQL = 'MOVE \\SERVER1\E$\PODPDF\TST\'+RTRIM(@myOrder)+'.pdf \\SERVER1\E$\PODPDF'
EXEC @result = master..xp_cmdshell @mySQL, NO_OUTPUT
WAITFOR DELAY '00:00:05'
END
END
DTS 包正在远程服务器上打开一个访问数据库并生成一个表单。如果我只运行存储过程但如果我使用触发器它永远不会完成。
求助!!!
【问题讨论】:
-
您真的还在使用 SQL 2000 和 DTS 吗?
-
我希望我可以拒绝,但公司目前无法更新。
-
您不能在触发器中执行此操作,因为数据尚未提交。在任何受支持的 SQL Server 版本中,您都需要使用 IDENTITY 键将这些命令写入另一个表,并让后台任务按顺序读取该表并执行命令。这是否也适用于 SQL 2000 我不能说:)
-
添加到这个。当执行此插入的事务失败并回滚时会发生什么?假设触发器工作,您现在将打印不存在的信息。问题?此外,使用替代触发器是令人担忧的 - 但也许您没有发布完整的触发器,因为缺少一些重要的东西。而且你在触发逻辑中也犯了一个严重的错误——假设插入了一行。
-
谢谢。触发器正在等待数据但数据尚不存在因此无法打印是有道理的。我将使用带有时间戳和计划任务的表中插入的记录来获取所有未处理的行并针对它们运行存储过程。我可以将其设置为每 5 分钟运行一次并带回接下来的 20 个订单。感谢您的帮助和澄清。
标签: sql-server stored-procedures triggers sql-server-2000