@Mikku 感谢我将数据读取为格式不佳的列...而不是单个列。我的错。这是处理单列数据的更新代码。我对数据类型做了简单的假设(并且将街道号码作为字符串保留,因为我不知道它们的真正结构)等等......但适用于有问题的数据示例:
Option Explicit
Public Sub check()
Dim vDataSheet As Worksheet
Dim vDataRow As Long
Dim vStreetNumber As String
Dim vStreetName As String
Dim vRefSheet As Worksheet
Dim vRefRow As Long
Dim vFromNumber As String
Dim vToNumber As String
Dim vFirstSpace As Long
Dim vSecondspace As Long
Dim vRefName As String
Dim vFound As Boolean
Set vDataSheet = Application.ActiveWorkbook.Sheets("Sheet1")
Set vRefSheet = Application.ActiveWorkbook.Sheets("Sheet2")
vDataRow = 1
While vDataSheet.Cells(vDataRow, 1) <> ""
vStreetNumber = Left(vDataSheet.Cells(vDataRow, 1), InStr(1, vDataSheet.Cells(vDataRow, 1), " ") - 1)
vStreetName = Right(vDataSheet.Cells(vDataRow, 1), Len(vDataSheet.Cells(vDataRow, 1)) - InStr(1, vDataSheet.Cells(vDataRow, 1), " "))
vFound = False
vRefRow = 1
While vRefSheet.Cells(vRefRow, 1) <> "" And Not vFound
vFirstSpace = InStr(1, vRefSheet.Cells(vRefRow, 1), " ")
vFromNumber = Left(vRefSheet.Cells(vRefRow, 1), vFirstSpace - 1)
vSecondspace = InStr(vFirstSpace + 1, vRefSheet.Cells(vRefRow, 1), " ")
vToNumber = Mid(vRefSheet.Cells(vRefRow, 1), vFirstSpace + 1, vSecondspace - vFirstSpace - 1)
vRefName = Right(vRefSheet.Cells(vRefRow, 1), Len(vRefSheet.Cells(vRefRow, 1)) - vSecondspace)
If vStreetNumber >= vFromNumber And vStreetNumber <= vToNumber And _
vStreetName = vRefName Then
vFound = True
End If
vRefRow = vRefRow + 1
Wend
If vFound Then
vDataSheet.Cells(vDataRow, 2) = "MATCH"
Else
vDataSheet.Cells(vDataRow, 2) = "NO MATCH"
End If
vDataRow = vDataRow + 1
Wend
End Sub
Sheet2
上的参考数据
Sheet1
上的匹配结果