ConnectN 检查对角线获胜答案

【问题标题】：ConnectN Checking for Diagonal WinsConnectN 检查对角线获胜
【发布时间】：2020-09-02 13:14:17
【问题描述】：

所以我目前正在编写代码来检查 connect3 游戏中的对角线获胜，但由于某种原因，没有显示打印语句，有人可以检查一下有什么问题

board = [['_','X','X','O'],
         ['_','X','X','O'],
         ['X','X','O','O']]
num_row = 3
num_col = 4
num_piece = 3 #game pieces needed to win 
game_piece = 'X'

# check / diagonal win
for rows in range(num_row - num_piece + 1):
    for cols in range(num_piece, num_col):
        index = 0
        for counts in range(num_piece):
            if board[rows + index][cols - index] == game_piece:
                index += 1
            else:
                break
            if index == num_piece:
                print('game end')

【问题讨论】：

标签： python list

【解决方案1】：

您的代码只测试第一个对角线（从右上角开始）：

>>> for rows in range(num_row - num_piece + 1):
...     for cols in range(num_piece, num_col):
...         index = 0
...         print(f"testing {rows, cols}")
...         for counts in range(num_piece):
...             if board[rows + index][cols - index] == game_piece:
...                 index += 1
...             else:
...                 break
...             if index == num_piece:
...                 print('game end')
...
testing (0, 3)

由于您要测试从第 2 列（第 3 列）开始的每个对角线，因此您希望从该范围的开头减去 1：

>>> for rows in range(num_row - num_piece + 1):
...     for cols in range(num_piece - 1, num_col):
...         index = 0
...         print(f"testing {rows, cols}")
...         for counts in range(num_piece):
...             if board[rows + index][cols - index] == game_piece:
...                 index += 1
...             else:
...                 break
...             if index == num_piece:
...                 print('game end')
...
testing (0, 2)
game end
testing (0, 3)

另请参阅：Finding neighbor cells in a grid with the same value. Ideas how to improve this function?

【讨论】：