在 Snowflake 中创建带有变量的视图答案

【问题标题】：Creating a View with Variables in Snowflake在 Snowflake 中创建带有变量的视图
【发布时间】：2021-06-02 08:03:10
【问题描述】：

我有以下看法：

create or replace view my_database_name.my_schema_name.d_dates as (

  /*
      Declare variables
  */
    set (start_date) = ('2017-07-01');
    set (end_date) = ('2022-06-30');

  /*
  */
  with part_1 as (

    select top 20000
        -1 + row_number() over(order by 0) as i_value
        , start_date + i_value as generated_date 
    from 
        (
            select 
                cast($start_date as date) as start_date
               ,cast($end_date as date) as end_date
        )
    inner join table
        (generator(rowcount => 100000 )) x
    /*
      Qualify filters the results of window functions
    */
    qualify 
        i_value < 1 + end_date - start_date

  )

  select
      (a.i_value + 1) as "date_id"
      ,a.generated_date as "date"
  from
      part_1 as a
  order by
      "date";
    

)

我收到以下错误消息：

SQL compilation error: syntax error line 6 at position 4 unexpected 'set'. syntax error line 6 at position 21 unexpected '='.

关于如何解决此问题的任何建议？

【问题讨论】：

标签： sql view snowflake-cloud-data-platform

【解决方案1】：

您可以使用表函数 (UDTF) 实现您在问题中描述的内容开始和结束日期将是函数的参数。

CREATE OR REPLACE FUNCTION my_database_name.my_schema_name.d_dates (start_date date, end_date date)
RETURNS TABLE (date_id number, generated_date date)
LANGUAGE SQL
AS
'
with part_1 as (

    select top 20000
        -1 + row_number() over(order by 0) as i_value
        , start_date + i_value as generated_date 
    from 
        (
            select 
                cast(start_date as date) as start_date
               ,cast(end_date as date) as end_date
        )
    inner join table
        (generator(rowcount => 100000 )) x
    /*
      Qualify filters the results of window functions
    */
    qualify 
        i_value < 1 + end_date - start_date

  )

  select
      (a.i_value + 1) as date_id
      ,a.generated_date as generated_date
  from
      part_1 as a
  order by
      2;
'
;

Your SQL needs more tweaking I think like not using date as a column name but this should work

【讨论】：

【解决方案2】：

Snowflake 中的视图不能承载变量设置或参数化。但是，您可以通过使用 SQL 或 Javascript 的用户定义表函数来实现您的目标：

https://docs.snowflake.com/en/sql-reference/udf-table-functions.html https://docs.snowflake.com/en/sql-reference/udf-js-table-functions.html

【讨论】：