【发布时间】：2014-04-14 22:19:02
【问题描述】：
我是 android 编程新手，任何人都可以帮我在我的 android 设备中找到所有 .mp3 文件。
【问题讨论】：
【发布时间】：2014-04-14 22:19:02
【问题描述】：
您应该使用 MediaStore。这是我用于类似内容的示例代码：
private static ArrayList<SongModel> LoadSongsFromCard() {
ArrayList<SongModel> songs = new ArrayList<SongModel>();
// Filter only mp3s, only those marked by the MediaStore to be music and longer than 1 minute
String selection = MediaStore.Audio.Media.IS_MUSIC + " != 0"
+ " AND " + MediaStore.Audio.Media.MIME_TYPE + "= 'audio/mpeg'"
+ " AND " + MediaStore.Audio.Media.DURATION + " > 60000";
final String[] projection = new String[] {
MediaStore.Audio.Media._ID, //0
MediaStore.Audio.Media.TITLE, //1
MediaStore.Audio.Media.ARTIST, //2
MediaStore.Audio.Media.DATA, //3
MediaStore.Audio.Media.DISPLAY_NAME
};
final String sortOrder = MediaStore.Audio.AudioColumns.TITLE
+ " COLLATE LOCALIZED ASC";
Cursor cursor = null;
try {
// the uri of the table that we want to query
Uri uri = MediaStore.Audio.Media.EXTERNAL_CONTENT_URI; //getContentUriForPath("");
// query the db
cursor = _context.getContentResolver().query(uri,
projection, selection, null, sortOrder);
if (cursor != null) {
cursor.moveToFirst();
while (!cursor.isAfterLast()) {
//if (cursor.getString(3).contains("AwesomePlaylists")) {
SongModel GSC = new SongModel();
GSC.ID = cursor.getLong(0);
GSC.songTitle = cursor.getString(1);
GSC.songArtist = cursor.getString(2);
GSC.path = cursor.getString(3);
// This code assumes genre is stored in the first letter of the song file name
String genreCodeString = cursor.getString(4).substring(0, 1);
if (!genreCodeString.isEmpty()) {
try {
GSC.genre = Short.parseShort(genreCodeString);
} catch (NumberFormatException ex) {
Random r = new Random();
GSC.genre = (short) r.nextInt(4);
} finally {
songs.add(GSC);
}
}
//}
cursor.moveToNext();
}
}
} catch (Exception ex) {
} finally {
if (cursor != null) {
cursor.close();
}
}
return songs;
}
【讨论】：
-
什么是 SongModel 类？？
public ArrayList<String> searchMP3File(ArrayList<String> aListFilePath, String rootPath) {
File rootFile = new File(rootPath);
File[] aRootFileFilter = rootFile.listFiles(new FileFilter() {
@Override
public boolean accept(File pathname) {
if(pathname.getName().endsWith(".mp3"))
return true;
else
return false;
}
});
if(aRootFileFilter != null && aRootFileFilter.length > 0) {
for(int i = 0; i < aRootFileFilter.length; i++) {
aListFilePath.add(aRootFileFilter[i].getPath());
}
}
File[] aRootFile = rootFile.listFiles();
for(int i = 0; i < aRootFile.length; i++) {
if(aRootFile[i].isDirectory()) {
ArrayList<String> aListSubFile = searchMP3File(aListFilePath, aRootFile[i].getPath());
if(aListSubFile != null && aListSubFile.size() > 0)
aListFilePath = aListSubFile;
}
}
return aListFilePath;
}
【讨论】：
当然。你可以 。代码未测试。
File dir =new File(Environment.getExternalStorageDirectory());
if (dir.exists()&&dir.isDirectory()){
File[] files=dir.listFiles(new FilenameFilter(){
@Override
public boolean accept(File dir,String name){
return name.contains(".mp3");
}
});
}
【讨论】：
您可以使用递归搜索。将此函数与您要开始搜索 .mp3 文件的目录路径一起使用（例如“/mnt/sdcard”）。
public Vector<String> mp3Files = new Vector<String>();
private void searchInDirectory(String directory)
{
File dir = new File(directory);
if(dir.canRead() && dir.exists() && dir.isDirectory())
{
String []filesInDirectory = dir.list();
if(filesInDirectory != null)
{
for(int i=0; i<filesInDirectory.length; i++)
{
File file = new File(directory+"/"+filesInDirectory[i]);
if(file.isFile() && file.getAbsolutePath().toLowerCase(Locale.getDefault()).endsWith(".mp3"))
{
mp3Files.add(directory+"/"+filesInDirectory[i]);
}
else if(file.isDirectory() )
{
searchInDirectory(file.getAbsolutePath());
}
}
}
}
}
【讨论】：
-
如果我想获取所有文件夹中的所有文件，而不仅仅是 /mnt/sdcard 中的所有文件呢？？
private String[] videoExtensions;
videoExtensions = new String[2];
videoExtensions[0] = "mp3";
videoExtensions[1] = "3gp";
在你的 onCreate() 方法中声明这个之后，在一些方法中设置下面的代码并调用它。根据您的需要在我的代码中进行更改。
试试{
File file = new File("mnt/sdcard/DCIM/Camera");
File[] listOfFiles = file.listFiles();
videoArray = new ArrayList<HashMap<String, String>>();
videoHashmap = new HashMap<String, String>();
for (int i = videoIndex; i < listOfFiles.length; i++) {
File files = listOfFiles[i];
rowDataVideos = new HashMap<String, String>();
for (String ext : videoExtensions) {
if (files.getName().endsWith("." + ext)) {
videoHashmap.put("Video", files.getAbsolutePath());
videoArray.add(videoHashmap);
fileSize = files.length();
fileSizeInMb += convertSize(fileSize, MB);
thumb = ThumbnailUtils.createVideoThumbnail(files.getAbsolutePath(), MediaStore.Images.Thumbnails.MINI_KIND);
if (thumb != null) {
createTempDirectory();
try {
FileOutputStream out = new FileOutputStream(audiofile);
thumb.compress(Bitmap.CompressFormat.PNG, 90, out);
out.flush();
out.close();
} catch (Exception e) {
e.printStackTrace();
}
}
// Tue Apr 23 16:08:28 GMT+05:30 2013
lastModDate = new Date(files.lastModified()).toString();
dateTime = (dateToMilliSeconds(lastModDate) / 1000L);
rowDataVideos.put(VIDEOPATH, files.getAbsolutePath());
rowDataVideos.put(VIDEOSTATUS, "0");
rowDataVideos.put(VIDEOSIZEINMB, String.valueOf(fileSizeInMb));
rowDataVideos.put(VIDEODATE, String.valueOf(dateTime));
if (dateTime > (RESPONSE_TIMESTAMP_VIDEO / 1000L)) {
dataProvider.InsertRow(VIDEOS, rowDataVideos);
}
}
}
}
} catch (Exception e) {
e.printStackTrace();
}
【讨论】：