eslint 抛出错误

Question

我是新的 android 初学者并尝试部署 firebase 功能但显示一些错误如何解决这个问题请帮助我。

Firebase 数据库结构

用户表

• 用户
  • user_id
    • device_token : user_device_token
    • 名称：用户名

通知表

• 通知
  • to_user_id
    • notification_id
      • 来自：from_user_id

Error

Index.js

'use strict'

const functions = require('firebase-functions');
const admin = require('firebase-admin');
admin.initializeApp(functions.config().firebase);


/*
 * 'OnWrite' works as 'addValueEventListener' for android. It will fire the function
 * everytime there is some item added, removed or changed from the provided 'database.ref'
 * 'sendNotification' is the name of the function, which can be changed according to
 * your requirement
 */

exports.sendNotification = functions.database.ref('/notifications/{user_id}/{notification_id}').onWrite(event => {


	  /*
	   * You can store values as variables from the 'database.ref'
	   * Just like here, I've done for 'user_id' and 'notification'
	   */

	  const user_id = event.params.user_id;
	  const notification_id = event.params.notification_id;

	  console.log('We have a notification from : ', user_id);

	  /*
	   * Stops proceeding to the rest of the function if the entry is deleted from database.
	   * If you want to work with what should happen when an entry is deleted, you can replace the
	   * line from "return console.log.... "
	   */

	  if(!event.data.val()){

			return console.log('A Notification has been deleted from the database : ', notification_id);

		}

	  /*
	   * 'fromUser' query retreives the ID of the user who sent the notification
	   */

	  const fromUser = admin.database().ref(`/notifications/${user_id}/${notification_id}`).once('value');

	  return fromUser.then(fromUserResult => {

			const from_user_id = fromUserResult.val().from;

			console.log('You have new notification from  : ', from_user_id);

			/*
			 * The we run two queries at a time using Firebase 'Promise'.
			 * One to get the name of the user who sent the notification
			 * another one to get the devicetoken to the device we want to send notification to
			 */

			const userQuery = admin.database().ref(`/Users/${from_user_id}/Name`).once('value');
			const deviceToken = admin.database().ref(`/Users/${user_id}/device_token`).once('value');

			return Promise.all([userQuery, deviceToken]).then(result => {

			  const userName = result[0].val();
			  const token_id = result[1].val();

			  /*
			   * We are creating a 'payload' to create a notification to be sent.
			   */

			  const payload = {
					notification: {
					  title : "New Friend Request",
					  body: `${userName} has sent you request`,
					  icon: "default",
					
					}
				};

			  /*
			   * Then using admin.messaging() we are sending the payload notification to the token_id of
			   * the device we retreived.
			   */

				  return admin.messaging().sendToDevice(token_id, payload).then(response => {

						console.log('This was the notification Feature');

					});

			});

		});

	});

**cmd 显示错误**

C:\Users\TahirAliAwan\Desktop\Function>firebase 部署 === 部署到“videochat-96f75”... 我部署功能 运行命令：npm --prefix %RESOURCE_DIR% run lint 函数@ lint C:\Users\TahirAliAwan\Desktop\Function\functions 埃斯林特。 C:\Users\TahirAliAwan\Desktop\Function\functions\index.js 61:11 警告避免嵌套承诺承诺/不嵌套 84:14 警告避免嵌套承诺承诺/不嵌套 84:69 错误每个 then() 都应该返回一个值或抛出 promise/always-return ✖ 3 个问题（1 个错误，2 个警告） npm 错误！ Windows_NT 10.0.10586 npm 错误！ argv "C:\Program Files\nodejs\node.exe" "C:\Program Files\nodejs\node_modules\npm\bin\npm-cli.js" "--prefix" "C:\Users\TahirAliAwan\Desktop\函数\函数" "运行" "lint" npm 错误！节点 v6.11.5 npm 错误！ npm v3.10.10 npm 错误！代码生命周期 npm 错误！函数@ lint：eslint . npm 错误！退出状态 1 npm 错误！ npm 错误！函数@ lint 脚本“eslint .”失败。 npm 错误！确保您安装了最新版本的 node.js 和 npm。 npm 错误！如果这样做，这很可能是函数包的问题， npm 错误！不是 npm 本身。 npm 错误！告诉作者这在您的系统上失败： npm 错误！埃斯林特。 npm 错误！您可以通过以下方式获取有关如何为此项目打开问题的信息： npm 错误！ npm 错误功能 npm 错误！或者，如果这不可用，您可以通过以下方式获取他们的信息： npm 错误！ npm 所有者 ls 函数 npm 错误！上面可能有额外的日志输出。 npm 错误！请在任何支持请求中包含以下文件： npm 错误！ C:\Users\TahirAliAwan\Desktop\Function\npm-debug.log 错误：函数预部署错误：命令以非零退出代码终止1

Answer 1

在@PeterHaddad 提示和我的努力之后，我通过删除此行解决了这个问题 .then(response => { console.log('This was the notification Feature'); 并更新 nodejs。 谢谢大家。