您可以导入 Foundation 和 AppKit 模块,然后子类化 NSApplication。但是,如果您的 pyobjc 代码不是您的代码的入口点,那么这可能不是您想要的。可以提供更多关于你试图用 pyobjc 做什么的细节吗?
这是一个使用 pyobjc 制作简单状态栏应用程序的快速示例,无需使用 xcode:
import objc
from Foundation import *
from AppKit import *
from PyObjCTools import AppHelper
class MyApp(NSApplication):
def finishLaunching(self):
# Make statusbar item
statusbar = NSStatusBar.systemStatusBar()
self.statusitem = statusbar.statusItemWithLength_(NSVariableStatusItemLength)
self.icon = NSImage.alloc().initByReferencingFile_('icon.png')
self.icon.setScalesWhenResized_(True)
self.icon.setSize_((20, 20))
self.statusitem.setImage_(self.icon)
#make the menu
self.menubarMenu = NSMenu.alloc().init()
self.menuItem = NSMenuItem.alloc().initWithTitle_action_keyEquivalent_('Click Me', 'clicked:', '')
self.menubarMenu.addItem_(self.menuItem)
self.quit = NSMenuItem.alloc().initWithTitle_action_keyEquivalent_('Quit', 'terminate:', '')
self.menubarMenu.addItem_(self.quit)
#add menu to statusitem
self.statusitem.setMenu_(self.menubarMenu)
self.statusitem.setToolTip_('My App')
def clicked_(self, notification):
NSLog('clicked!')
if __name__ == "__main__":
app = MyApp.sharedApplication()
AppHelper.runEventLoop()
然后您可以使用 py2app 使其可分发:
from distutils.core import setup
import py2app
NAME = 'myapp'
SCRIPT = 'myapp.py'
VERSION = '0.1'
ID = 'myapp'
plist = dict(
CFBundleName = NAME,
CFBundleShortVersionString = ' '.join([NAME, VERSION]),
CFBundleGetInfoString = NAME,
CFBundleExecutable = NAME,
CFBundleIdentifier = 'com.yourdn.%s' % ID,
LSUIElement = '1', #makes it not appear in cmd-tab task list etc.
)
app_data = dict(script=SCRIPT, plist=plist)
setup(
app = [app_data],
options = {
'py2app':{
'resources':[
],
'excludes':[
]
}
}
)