与 ACAccountStore (iOS 5) 的 Twitter 集成问题

Question

当我使用 iOS 6.0 运行以下代码时，它可以正常工作

ACAccountStore *account = [[ACAccountStore alloc] init];
ACAccountType *accountType = [account accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];

[account requestAccessToAccountsWithType:accountType options:nil
                                  completion:^(BOOL granted, NSError *error)
     {
         dispatch_async(dispatch_get_main_queue(), ^{

             if (granted) 
             {
                 //MY CODE
             }
         });

     }];

当我使用 iOS 5.0 或 5.1 运行此代码时，它会崩溃并显示以下输出，

*** Terminating app due to uncaught exception 'NSInvalidArgumentException', 
reason: '-[ACAccountStore requestAccessToAccountsWithType:options:completion:]: 
unrecognized selector sent to instance 0x68a57c0'

不知道这个奇怪的崩溃日志..

请告诉我，如何摆脱这个..

Answer 1

使用以下方法：

[account requestAccessToAccountsWithType:accountType withCompletionHandler:^(BOOL granted, NSError *error)
 {

   if (granted) {

            //Your code
            }
        }
   }];

Answer 2

为此尝试更新：

ACAccountStore *account = [[ACAccountStore alloc] init];
ACAccountType *accountType = [account accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];

// iOS 6
if ( [account respondsToSelector:@selector(requestAccessToAccountsWithType: options: completion:)] )
{
[account requestAccessToAccountsWithType:accountType options:nil
                                  completion:^(BOOL granted, NSError *error)
     {
         dispatch_async(dispatch_get_main_queue(), ^{

             if (granted) 
             {
                 //MY CODE
             }
         });

     }];
}

// iOS 5
else if ( [account respondsToSelector:@selector(requestAccessToAccountsWithType: withCompletionHandler:)] )
{
[account requestAccessToAccountsWithType:accountType
                                  withCompletionHandler:^(BOOL granted, NSError *error)
     {
         dispatch_async(dispatch_get_main_queue(), ^{

             if (granted) 
             {
                 //MY CODE
             }
         });

     }];
}
else
{
// iOS 4 or less
}

Answer 3

这有点晚了，但您收到该错误的原因是 requestAccessToAccountsWithType:options:completion: 是 iOS 6 中的新功能。

在 iOS 5 及更早版本中，请改用 requestAccessToAccountsWithType:withCompletionHandler 方法（此方法在 iOS 6 中已弃用）

查看文档：https://developer.apple.com/library/ios/documentation/Accounts/Reference/ACAccountStoreClassRef/Reference/Reference.html#//apple_ref/doc/uid/TP40011021-CH1-SW12

Answer 4

感谢@CReaTuS，我想进一步澄清这一点，请注意，在 iOS6 的情况下，我们发出 SLRequest，而在 iOS5 中，我们必须使用 TWRequest 执行请求。见下文-

 ACAccountStore *accountStore = [[ACAccountStore alloc] init];
 ACAccountType *accountType = [accountStore accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];

 if ( [accountStore respondsToSelector:@selector(requestAccessToAccountsWithType: options: completion:)] )
 {
 [accountStore requestAccessToAccountsWithType:accountType options:nil
 completion:^(BOOL granted, NSError *error)
 {
 dispatch_async(dispatch_get_main_queue(), ^{

 if (granted)
 {
     // Get the list of Twitter accounts.
     NSArray *accountsArray = [accountStore accountsWithAccountType:accountType];

     // For the sake of brevity, we'll assume there is only one Twitter account present.
     // You would ideally ask the user which account they want to tweet from, if there is more than one Twitter account present.
     if ([accountsArray count] > 0) {
         // Grab the initial Twitter account to tweet from.
         ACAccount *twitterAccount = [accountsArray objectAtIndex:0];

         NSMutableDictionary *tempDict = [[NSMutableDictionary alloc] init];
         [tempDict setValue:@"Twitter_Name" forKey:@"screen_name"];
         [tempDict setValue:@"true" forKey:@"follow"];

        //Code specific to iOS6 or later

         SLRequest *followRequest = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:[NSURL URLWithString:@"https://api.twitter.com/1.1/friendships/create.json"] parameters:tempDict];

         // To unfollow hit URL-https://api.twitter.com/1.1/friendships/destroy.json

         [followRequest setAccount:twitterAccount];
         [followRequest performRequestWithHandler:^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error) {
             NSString *output = [NSString stringWithFormat:@"HTTP response status: %i", [urlResponse statusCode]];
             NSLog(@"%@", output);
             if (error) {
                 dispatch_async(dispatch_get_main_queue(), ^{
                     //Update UI to show follow request failed

                 });
             }
             else {
                 dispatch_async(dispatch_get_main_queue(), ^{
                     //Update UI to show success


                 });
             }
         }];
     }


 }
 });

 }];
 }
 else if ( [accountStore respondsToSelector:@selector(requestAccessToAccountsWithType: withCompletionHandler:)] )
 {
 [accountStore requestAccessToAccountsWithType:accountType withCompletionHandler:^(BOOL granted, NSError *error)
 {
 dispatch_async(dispatch_get_main_queue(), ^{

 if (granted)
 {         
     // Get the list of Twitter accounts.
     NSArray *accountsArray = [accountStore accountsWithAccountType:accountType];

     // For the sake of brevity, we'll assume there is only one Twitter account present.
     // You would ideally ask the user which account they want to tweet from, if there is more than one Twitter account present.
     if ([accountsArray count] > 0) {
         // Grab the initial Twitter account to tweet from.
         ACAccount *twitterAccount = [accountsArray objectAtIndex:0];

         NSMutableDictionary *tempDict = [[NSMutableDictionary alloc] init];
         [tempDict setValue:@"Twitter_Name" forKey:@"screen_name"];
         [tempDict setValue:@"true" forKey:@"follow"];

        //Code specific to iOS5

         TWRequest *followRequest = [[TWRequest alloc] initWithURL:[NSURL URLWithString:@"https://api.twitter.com/1/friendships/create.json"]
                                                      parameters:tempDict
                                                   requestMethod:TWRequestMethodPOST];


         [followRequest setAccount:twitterAccount];
         [followRequest performRequestWithHandler:^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error) {
             NSString *output = [NSString stringWithFormat:@"HTTP response status: %i", [urlResponse statusCode]];
             NSLog(@"%@", output);
             if (error) {
                 dispatch_async(dispatch_get_main_queue(), ^{
                     //Update UI to show follow request failed

                 });
             }
             else {
                 dispatch_async(dispatch_get_main_queue(), ^{
                     //Update UI to show success
                 });
             }
         }];
     }


 }
 });

 }];
 }
 else
 {
     dispatch_async(dispatch_get_main_queue(), ^{
         //Update UI to show follow request completely failed

     });
 }

编码愉快:)