【发布时间】:2019-04-16 02:44:32
【问题描述】:
简介
如果 google play 市场上有新版本,我有一个应用程序并希望强制用户更新它。这适用于以下代码,但不是很稳定。 我正在通过 AsyncTask 执行此操作并从 php 文件中获取数据。 但它让我感觉一定有更好的方法或者让它更稳定的方法。
问题
如何设置程序超时,例如由于用户的互联网连接非常低?
代码
get_newest_apk.php
<?PHP
/* GET APK VERSION FROM ANDROID DEVICE
Example: [PATH]/get_newest_apk.php?apkversion=6
*/
if($_GET["apkversion"]){
$apkversion= $_GET["apkversion"];
//MYSQL LOGIN PARAMETERS
$host = '*****';
$user = '*****';
$pass = '*****';
$db = '*****';
$mysqli = new mysqli($host, $user, $pass, $db);
$result = $mysqli->query("SELECT MAX(VERSION) FROM TBL_APK");
$row = $result->fetch_row();
$count = $row[0];
if($count > $apkversion){
//Newer APK is avaiable
echo "1";
}else{
//There is no never APK avaiable
echo "2";
}
}else{
//Error by GETTING apkversion from Android device
echo "3";
}
?>
AsyncTask 类
class checkForNewAPK extends AsyncTask<Void, Void, String> {
@Override
protected void onPreExecute() {
//Do not show the user a progress because he don't want to see it in every onResume
}
@Override
protected void onPostExecute(String s) {
super.onPostExecute(s);
int intResult = Integer.parseInt(s);
//strResult as intResult; 1 = Newer APK avaiable, 2 = No newer APK avaiable, 3 = Error at $_GET["apkversion"] line 6
if(intResult == 1){
//Force to Update App
Log.v("APKResult: ", "1");
}else if(intResult == 2){
//No update needed
Log.v("APKResult: ", "2");
}else if(intResult == 3){
//Error in PHP-File
Log.v("APKResult: ", "3");
}else{
//Unknown error
Log.v("APKResult: ", "Unkown Error");
}
}
//in this method we are fetching the json string
@Override
protected String doInBackground(Void... voids) {
try {
int intApkVersion = getApplication().getPackageManager().getPackageInfo(getPackageName(), 0).versionCode;
URL url = new URL(strUrlGetNewestAPK+"?apkversion="+intApkVersion);
String strResultFromEcho;
HttpURLConnection con = (HttpURLConnection) url.openConnection();
StringBuilder strResult = new StringBuilder();
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(con.getInputStream()));
while ((strResultFromEcho = bufferedReader.readLine()) != null) {
strResult.append(strResultFromEcho + "\n");
}
return strResult.toString().trim();
} catch (Exception e) {
return null;
}
}
}
【问题讨论】:
-
请编辑问题以将其限制为具有足够详细信息的特定问题,以确定适当的答案。避免一次问多个不同的问题。请参阅How to Ask 页面以获得澄清此问题的帮助。问题目前有被近距离投票为Too Broad的风险
-
我确实编辑了这个问题。谢谢!
标签: php android mysql httpurlconnection stringbuilder