【问题标题】:Snowflake - Dense_rank starting at 2 rather than 1雪花 - Dense_rank 从 2 而不是 1 开始
【发布时间】:2021-11-17 21:04:47
【问题描述】:
我在查询中使用以下语句:
CASE WHEN apercent IS NULL THEN NULL ELSE dense_rank() over (partition by adate order by apercent desc) END as arank
由于某种原因,排名结果从 2 而不是 1 开始。没有并列值,但有一些 NULL 值。我假设这是因为 NULL。有什么方法可以更新它以强制排名从 1 开始?
当前结果:
| arank |
apercent |
| 2 |
23.57 |
| 3 |
13.61 |
| 4 |
10.67 |
| 5 |
6.14 |
| 6 |
6.00 |
| 7 |
5.79 |
| 8 |
5.57 |
| 9 |
5.27 |
| 10 |
4.80 |
| NULL |
NULL |
期望的结果:
| arank |
apercent |
| 1 |
23.57 |
| 2 |
13.61 |
| 3 |
10.67 |
| 4 |
6.14 |
| 5 |
6.00 |
| 6 |
5.79 |
| 7 |
5.57 |
| 8 |
5.27 |
| 9 |
4.80 |
| NULL |
NULL |
【问题讨论】:
标签:
sql
snowflake-cloud-data-platform
dense-rank
【解决方案1】:
如果您的百分比不能为负数,您可以使用 coalesce 来模仿 nulls last
case when apercent is null then null
else dense_rank() over (partition by adate order by coalesce(apercent,0.00) desc)
end as arank
【解决方案2】:
一个简单的解决方案是使用NULLS LAST:
(CASE WHEN apercent IS NOT NULL
THEN dense_rank() over (partition by adate order by apercent desc nulls last)
END) as arank
或者,您可以按NULL 值进行分区,这样它们就不会包含在非NULL 值的计数中:
(CASE WHEN apercent IS NOT NULL
THEN dense_rank() over (partition by adate, apercent is null order by apercent desc)
END) as arank