【发布时间】:2011-07-05 21:48:36
【问题描述】:
请帮助我理解这一点:-
(gdb) info frame
Stack level 0, frame at 0xb75f7390:
eip = 0x804877f in base::func() (testing.cpp:16); saved eip 0x804869a
called by frame at 0xb75f73b0
source language c++.
Arglist at 0xb75f7388, args: this=0x0
Locals at 0xb75f7388, Previous frame's sp is 0xb75f7390
Saved registers:
ebp at 0xb75f7388, eip at 0xb75f738c
“ebp, eip Locals at and Previous Frame's sp”是什么意思?请解释
【问题讨论】:
标签: gdb